Question Video: Solving a Quadratic Equation in Its Factored Form | Nagwa Question Video: Solving a Quadratic Equation in Its Factored Form | Nagwa

Question Video: Solving a Quadratic Equation in Its Factored Form Mathematics • Second Year of Preparatory School

Identify the solutions to the equation (𝑥 − 3)(𝑥 + 8) = 0.

01:50

Video Transcript

Identify the solutions to the equation 𝑥 minus three multiplied by 𝑥 plus eight is equal to zero.

In this question, we have the product of two binomial expressions, 𝑥 minus three and 𝑥 plus eight. And we’re told that this product is equal to zero. In fact, what we have is the factored form of a quadratic equation. We’re asked to identify the solutions to this equation, which means we need to determine the values of 𝑥 that satisfy the equation.

To do this, we recall that the only way the product of two values can be zero is if at least one of the values is itself equal to zero. So either the value of 𝑥 minus three or the value of 𝑥 plus eight must be equal to zero. This gives two simple linear equations that we need to solve. The first equation can be solved by adding three to each side to give 𝑥 equals three. The second equation can be solved by subtracting eight from each side, leading to 𝑥 equals negative eight.

These are the two solutions to the given equation. When 𝑥 equals three, the first expression in the product equals zero. And when 𝑥 equals negative eight, the second expression in the product equals zero. In both cases, this makes the overall product zero as required.

The solutions to the given equation, which is a quadratic equation in its factored form, are 𝑥 equals three or equals negative eight.

Join Nagwa Classes

Attend live sessions on Nagwa Classes to boost your learning with guidance and advice from an expert teacher!

  • Interactive Sessions
  • Chat & Messaging
  • Realistic Exam Questions

Nagwa uses cookies to ensure you get the best experience on our website. Learn more about our Privacy Policy