### Video Transcript

Evaluate the limit of π₯ squared
over π to the π₯ as π₯ approaches β using LβHΓ΄pitalβs rule.

We might try to evaluate this limit
by using the fact that the limit of a quotient of functions is a quotient of their
limits. So we get the limit of π₯ squared
as π₯ approaches β over the limit of π to the π₯ of the π₯ and π₯ approaches
β. The problem is that the limit of π₯
squared as π₯ approaches β is β as is the limit of π to the π₯ as π₯
approaches β. And so we get the indeterminate
form β over β. This is why we need to use
LβHΓ΄pitalβs rule. LβHΓ΄pitalβs rule says that if the
quotient of limits, the limit of π of π₯ as π₯ approaches π over the limit of π
of π₯ as π₯ approaches π, gives an indeterminate form. Thatβs zero over zero or a positive
or negative β over a positive or negative β. Then the limit of the quotient of
functions π of π₯ over π of π₯ as π₯ approaches π is equal the limit of the
quotient of their derivatives π prime of π₯ over π prime of π₯ as π₯ approaches
π.

Of course, this only works if π
and π differentiable functions. But in our case, they are π of π₯
is π₯ squared, which is differentiable, as of π of π₯, which is π to the π₯. With this choice of π of π₯ and π
of π₯, weβve already seen that the quotient to their limits gives the indeterminate
form β over β. So LβHΓ΄pitalβs rule does apply. And hence, we can say that the
limit of the quotient of functions that weβre looking for is equal to the limit of
the quotient of their derivatives. π of π₯ is π₯ squared, and so π
prime of π₯ is two π₯, its derivative. π of π₯ is π to the π₯, and its
derivative is also π to the π₯. The exponential function π to the
π₯ has the property that its derivative is just itself.

Now, we can try to use the fact
that the limit of a quotient of functions is a quotient of their limits. What is the limit of two π₯ as π₯
approaches β. Well, as π₯ approaches β,
two π₯ does as well. And the same is true in the
denominator. The limit of π to the π₯ as π₯
approaches β, as weβve really seen, is also β. We have another indeterminate form
here, β over β. You might think that we havenβt
actually made any progress by applying the LβHΓ΄pitalβs rule. But in fact, we have. And we can see this by applying the
LβHΓ΄pitalβs rule one more time. This time weβre applying it to the
limit of two π₯ over π to the π₯ as π₯ approaches β. And hence, we take π of π₯ to be
two π₯ and π of π₯ to be π to the π₯.

The derivative of two π₯ is two and
the derivative of π to the π₯ is π to the π₯. And so applying LβHΓ΄pitalβs rule a
second time, we get the limit of two over π to the π₯ as π₯ approaches
β. Now, we can use the fact that the
limit of a quotient is a quotient of the limits. The limit of two as π₯ approaches
β is just two, and the limit of π to the π₯ as π₯ approaches β is
β. Two over β isnβt an
indeterminate form, although it contains β, which isnβt itself a real
number. In the context of limits, we can
see that any real number over β is zero. And so thatβs the value of our
initial limit, the limit of π₯ squared over π to the π₯ as π₯ approaches β
as well.

If youβre worried about saying that
two divided by β is zero, then thereβs another way of saying this. Instead of finding a quotient of
limits, we can think of the function two over π to the π₯ or two π to the negative
π₯. You might recognize this as an
exponential decay, π to the negative π₯. And hence, two times π to the
negative π₯ approaches zero as π₯ approaches β. Either way, the answer is zero.