### Video Transcript

What is the equation of the line
with π₯-intercept negative three and π¦-intercept four?

So the first thing weβre gonna do
in this question is sketch our line. So what weβve got first of all is
an π₯-intercept of negative three, which means we know that our line crosses the
π₯-axis at negative three. And we have a π¦-intercept at
four. So it crosses our π¦-axis at
four. So now if we join these points, we
have our straight line. So what we want to do now is find
its equation. And the form in which weβre gonna
find the equation first of all is the point-slope form, which is π¦ minus π¦ sub one
equals π multiplied by π₯ minus π₯ sub one. And the reason weβre going to do
this is because itβs the easiest way to tackle the problem because what we can do is
identify specific points on the line easily and we know the intercepts.

So therefore, we can easily work
out the slope. And as you can see from the
point-slope form, what we need is the slope, which is π, and a point on the line π₯
sub one, π¦ sub one. It is also worth noting that you
might also see the point-slope form as π¦ minus π΄ equals π multiplied by π₯ minus
π΅, which is exactly the same. Theyβre just giving the coordinates
of the point as π΄, π΅.

So what we know is that the
π₯-intercept is negative three and the π¦-intercept is four. So therefore, we have two points:
negative three, zero and zero, four. So the first thing we want to do is
find the slope of our line. And we can do that using a
formula. And that formula is π is equal to
π¦ sub two minus π¦ sub one over π₯ sub two minus π₯ sub one, so the change in π¦
over the change in π₯.

So to help us use this formula,
what weβve done is labeled our points. So weβve got π₯ sub one, π¦ sub one
and π₯ sub two, π¦ sub two. So if we substitute these values
in, we get π equals four minus zero over zero minus negative three, which is gonna
give us π is equal to four over three or a slope of four-thirds. Itβs worth noting that it doesnβt
matter which way round weβd labeled our points because it still wouldβve given us
the same slope.

So great, we now have our slope,
and we also know a point on our line. So therefore, we can substitute our
information into the point-slope form. We could choose any point along our
line. However, Iβm just gonna choose here
the first point that weβve got, which is negative three, zero. As we said, any point on our line
would work. So when we substitute in our π₯ sub
one, π¦ sub one, what weβre gonna get is π¦ minus zero is equal to four-thirds
multiplied by π₯ minus negative three. So if we take a look at the
right-hand side, what we get is π¦ equals four-thirds multiplied by π₯ plus
three. So this is the equation in the
point-slope form.

But we could also write it in
standard form. So to do this, what we do is
multiply the whole thing through by three to give us three π¦ equals four multiplied
by π₯ plus three. Then distributing across
parentheses gives us three π¦ equals four π₯ plus 12. And then, finally, we can subtract
four π₯, which gives us three π¦ minus four π₯ equals 12. So therefore, weβve got the
equation in both the point-slope form and standard form.