### Video Transcript

Determine the limit as π₯
approaches negative four of π₯ squared minus nine π₯ plus two all divided by
negative eight π₯ squared minus three π₯ minus nine.

When asked to evaluate a limit, the
first thing we should try is direct substitution. We can notice that weβre asked to
evaluate the limit of a rational function. Thatβs the quotient of two
polynomials, π of π₯ divided by π of π₯. And we recall that we can evaluate
the limit as π₯ approaches some finite value of π of a rational function by using
direct substitution if the polynomial in the denominator evaluated at π does not
give us zero. This gives us that the limit as π₯
approaches π of our function π of π₯ is equal to π evaluated at π.

In fact, even if the polynomial in
our denominator evaluated at π was equal to zero, we could check if the polynomial
in our numerator evaluated at π was also equal to zero. We could then apply the factor
theorem to note that both of our polynomials share a factor of π₯ minus π. Cancelling this shared factor of π₯
minus π would then give us a new rational function, which agrees everywhere with
our old rational function π of π₯ except to the point where π₯ is equal to π. We could then attempt to use direct
substitution on this new rational function to evaluate our limit.

We want to calculate the limit as
π₯ approaches negative four. So, weβll set π equal to negative
four. And weβll set π of π₯ equal to the
polynomial in the numerator of our limit. Thatβs π₯ squared minus nine π₯
plus two. And weβll set π of π₯ equal to the
polynomial in the denominator of our limit. Thatβs negative eight π₯ squared
minus three π₯ minus nine.

We now need to check the output of
our denominator when we input π₯ is equal to negative four. Substituting π₯ is equal to
negative four into our polynomial π of π₯ gives us negative eight times negative
four squared minus three times negative four minus nine. And we can simplify this to give us
negative 128 plus 12 minus nine, which is equal to negative 125. And, in particular, this is not
equal to zero. So, we can use direct substitution
to evaluate the limit given to us in the question.

So by using direct substitution, we
have the limit as π₯ approaches negative four of π₯ squared minus nine π₯ plus two
all divided by negative eight π₯ squared minus three π₯ minus nine is equal to
negative four squared minus nine times negative four plus two all divided by
negative eight times negative four squared minus three times negative four minus
nine. We can simplify this calculation
since the denominator is equal to π evaluated at negative four, which weβve already
found to be equal to negative 125.

So, we now only need to calculate
our numerator. We have negative four squared is
equal to 16. And then, we subtract nine times
negative four which is positive 36. And then, we add two. And we can simplify this to give us
negative 54 divided by 125.

Therefore, weβve shown the limit as
π₯ approaches negative four of π₯ squared minus nine π₯ plus two all divided by
negative eight π₯ squared minus three π₯ minus nine is equal to negative 54 divided
by 125.