Question Video: Differentiating Trigonometric Functions Using the Chain Rule | Nagwa Question Video: Differentiating Trigonometric Functions Using the Chain Rule | Nagwa

# Question Video: Differentiating Trigonometric Functions Using the Chain Rule Mathematics • Second Year of Secondary School

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If π¦ = sin (17/π₯βΉ), find dπ¦/dπ₯.

03:18

### Video Transcript

If π¦ equals sin of 17 over π₯ to the ninth power, find dπ¦ by dπ₯.

What we have here is an example of a composite function. We have the function 17 over π₯ to the ninth power, and then weβre taking the sine of this function. So, we have a function of a function. In order to find the derivative of a composite function, we need to recall the chain rule. The chain rule says that if π¦ is some function of π’ and π’ is some function of π₯, then dπ¦ by dπ₯ is equal to dπ¦ by dπ’ multiplied by dπ’ by dπ₯. Letβs see what applying the chain would look like in this question.

Weβre going to let π’ equal the inner part of our composite function. So, thatβs 17 over π₯ to the ninth power. Or we can write this using negative exponents as 17π₯ to the power of negative nine. Then, as π¦ is equal to sin of 17 over π₯ to the ninth power and π’ is equal to 17 over π₯ to the ninth power, π¦ will be equal to sin of π’. And so, we have π¦ as a function of π’ and π’ as a function of π₯. In order to apply the chain rule, we need to find their derivatives. Thatβs dπ’ by dπ₯ and dπ¦ by dπ’.

To find dπ’ by dπ₯, we need to recall the power rule of differentiation, which tells us that to differentiate a power of π₯, we multiply by that power or exponent, and then reduce the exponent by one. So, the derivative of 17π₯ to the power of negative nine will be 17 multiplied by negative nine π₯ to the power of negative 10. Which simplifies to negative 153π₯ to the power of negative 10. To find dπ¦ by dπ’, we need to recall our standard results for differentiating trigonometric functions. And remember here, the argument of the trigonometric function must be given in radians.

We recall that the derivative of sin π’ with respect to π’ is cos π’. So, we have that dπ¦ by dπ’ equals cos π’. Now, we can substitute into the chain rule. This tells us that dπ¦ by dπ₯ is equal to dπ¦ by dπ’, so thatβs cos π’, multiplied by dπ’ by dπ₯, which is negative 153π₯ to the power of negative 10. Now, we have an expression for dπ¦ by dπ₯, but itβs in terms of two variables, the variable π’ and the variable π₯. And we need it to be in terms of our original variable only. So, the final step is to reverse our substitution.

Remember that we defined π’ to be equal to 17 over π₯ to the ninth power. So, we undo our substitution by replacing π’ with 17 over π₯ to the ninth power. And at the same time, we can write negative 153π₯ to the power of negative 10 as negative 153 over π₯ to the 10th power. And so, we have our expression for dπ¦ by dπ₯. By using the chain rule which, remember, tells us how to find the derivative of a composite function, weβve found that dπ¦ by dπ₯ is equal to negative 153 over π₯ to the 10th power cos of 17 over π₯ to the ninth power.

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