### Video Transcript

If π and π are two real functions
where π of π₯ is π₯ plus nine over π₯ squared plus 15π₯ plus 54 and π of π₯ is
equal to π₯ plus eight, determine the value of π minus π of negative six if
possible.

We begin by recalling that π minus
π of π₯ is simply the function π minus the function π. So, letβs evaluate π minus π of
π₯ first and then consider its domain. Weβre given that π is the rational
function π₯ plus nine over π₯ squared plus 15π₯ plus 54 and π is the function π₯
plus eight. So, π minus π of π₯ is π₯ plus
nine over π₯ squared plus 15π₯ plus 54 minus eight plus π₯. Weβre actually going to simplify
this expression by subtracting the fractions. And to do so, weβre going to write
π₯ plus eight as π₯ plus eight over one then create a common denominator.

To achieve this common denominator,
weβre going to need to multiply the numerator and denominator of our second fraction
by π₯ squared plus 15π₯ plus 54. And when we do, our second fraction
becomes π₯ plus eight times π₯ squared plus 15π₯ plus 54. Letβs distribute the parentheses in
our second fraction. When we do, the numerator becomes
π₯ cubed plus 15π₯ squared plus eight π₯ squared plus 120π₯ plus 54π₯ plus 432,
which simplifies to π₯ cubed minus 23π₯ squared plus 174π₯ plus 432.

Now that our denominators are
equal, weβre going to subtract every term in the numerator of our second fraction
from the numerator of the first, giving us π minus π of π₯ as negative π₯ cubed
plus 23π₯ squared minus 173π₯ minus 423 all over π₯ squared plus 15π₯ plus 54.

Now, before we find the value of π
minus π of negative six, letβs consider the domain of our function. Remember, the domain is the set of
inputs that will yield a real output. And so, whenever weβre calculating
the domain of a rational function like this one, we need to consider the fact that
the denominator of this fraction cannot be equal to zero. We donβt want to be dividing by
zero. And so, weβre just going to begin
by calculating the values of π₯ where this expression is equal to zero, where π₯
squared plus 15π₯ plus 54 equals zero.

To do this, weβre going to factor
the expression on the left-hand side. We know that the term at the front
of each binomial must be π₯ since π₯ times π₯ gives us π₯ squared. Then, we find two numbers whose
product is 54 and whose sum is 15. Thatβs nine and six. So, we have π₯ plus nine times π₯
plus six equals zero. Well, for the product of two
numbers to be equal to zero, either one of those numbers must themselves be equal to
zero. So, π₯ plus nine must be equal to
zero or π₯ plus six must be equal to zero.

If we subtract nine from both sides
of our first equation, we find π₯ is equal to negative nine. And if we subtract six from both
sides of our second equation, π₯ is equal to negative six. And so, we see that the denominator
of our fraction will be equal to zero if π₯ is equal to negative six or π₯ is equal
to negative nine. So, the domain of our function π
minus π of π₯ must be all real numbers not including negative six and negative
nine. We can use set notation as shown to
demonstrate this.

Now, we were looking to evaluate π
minus π of negative six, but we said that negative six is not in the domain of the
function π minus π of π₯. And so, weβre, therefore, unable to
evaluate π minus π of negative six. We say that itβs undefined.