Lesson Video: Laws of Exponents over the Real Numbers | Nagwa Lesson Video: Laws of Exponents over the Real Numbers | Nagwa

Lesson Video: Laws of Exponents over the Real Numbers Mathematics • Second Year of Preparatory School

In this video, we will learn how to apply the laws of exponents to multiply and divide powers and to calculate a power raised to a power over the real numbers.

18:05

Video Transcript

In this video, we will learn how to apply the laws of exponents to multiply and divide powers and to calculate a power raised to a power over the real numbers. We should already be familiar with what powers are and the key laws of exponents. But we we’ll recap them briefly here.

A power is an expression of the form 𝑎 to the power of 𝑚, where 𝑎 and 𝑚 are each real numbers. 𝑎 is called the base and 𝑚 is called the exponent. If we’re able to evaluate this power, so if we can write 𝑎 to the power of 𝑚 is equal to 𝑐, then 𝑐 is the result. For example, two cubed or two to the third power is equal to eight. For positive integer exponents, such as the exponent of three we have here, we can think of powers as the number of bases that we multiply together. So two cubed means two times two times two; it’s three twos multiplied together.

There are several laws of exponents which we should already be familiar with. Each of these apply for real values of the base 𝑎. And for now, we’ll just be concerned with integer values of the exponents. First, we have the product rule for exponents, which tells us how to find the exponent when we have a product of powers of the same base. We add the powers. 𝑎 to the power of 𝑚 multiplied by 𝑎 to the power of 𝑛 is 𝑎 to the power of 𝑚 plus 𝑛. So for example, seven squared multiplied by seven cubed is seven to the power of two plus three; that’s seven to the power of five. We can demonstrate this rule at least for positive integer exponents by writing the expression out longhand. 𝑎 to the power of 𝑚 multiplied by 𝑎 to the power of 𝑛 is 𝑚 lots of 𝑎 multiplied together multiplied by 𝑛 lots of 𝑎 multiplied together. So overall, we’re multiplying 𝑚 plus 𝑛 lots of 𝑎 together. And so this is the exponent for the result.

We do need to be careful when working with this rule because there are two really common mistakes. The first is to multiply rather than add the exponents. The second is to multiply the bases or indeed make both mistakes and multiply both the bases and the exponents. But if we remember why this rule holds, then we shouldn’t make these mistakes. Now, even though we demonstrated the logic behind this rule using positive integer exponents, it does in fact apply when the exponents are any real values.

Next, we have the quotient rule for exponents, which tells us how to find the exponent when we are dividing two powers of the same base. This time, we subtract the powers. We can again demonstrate this rule for positive integer values of 𝑚 and 𝑛 by writing a quotient out longhand and then canceling common factors in the numerator and denominator. Here, we are assuming that 𝑚 is greater than or equal to 𝑛, but the result is also true if 𝑛 is greater than 𝑚. Next, we have the power rule for exponents, which tells us that if we’re raising a base to a power and then to another power, overall, we’re raising that base to the product of those powers.

Those are the three main rules, but there are also some additional ones that we need to recall. If we’re finding the power of a product, this is the same as raising each factor to the power and then finding the product. And if we’re finding the power of a quotient, this is the same as raising both the numerator and denominator of that quotient to the power separately. We should already be comfortable applying each of these rules when the base is an integer or a fractional value. The focus of this video will be to extend our knowledge to applying these rules to the entire set of real numbers. So we’re now including irrational numbers as bases.

As we’re going to be working with any real number here, we need to introduce some further rules for simplifying expressions involving square roots. They are as follows. For an expression with a real base 𝑎, which must be nonnegative, the square root of 𝑎 squared is equal to 𝑎 and the square root or 𝑎 squared is also equal to 𝑎. It is important that 𝑎 is nonnegative here so that its square root is well defined in the first rule and so that we have a unique answer when squaring and then square rooting in the second. Let’s now consider our first example, in which we’ll see how to use the product rule for exponents to simplify an expression with a real base.

Fill in the blank. The expression root three multiplied by root three squared multiplied by root three cubed simplifies to blank.

We need to simplify this expression which consists of three powers of the same base, root three, multiplied together. We can therefore apply the product rule for exponents, which states that for real values of 𝑎, 𝑚, and 𝑛, 𝑎 to the power of 𝑚 multiplied by 𝑎 to the power of 𝑛 is equal to 𝑎 to the power of 𝑚 plus 𝑛. Now there’s no exponent written for the first term in the product, but we know that any number is equal to that number to the first power. So root three is root three to the power of one. So applying the product rule and summing all three exponents, we have that this expression simplifies to root three to the power of one plus two plus three, which is root three to the sixth power. We now know that we have six lots of root three multiplied together, which we can write out longhand.

Next, we see that we can group the terms in this product into pairs. And hence, we can express the product as root three squared multiplied by root three squared multiplied by root three squared. We can then recall the result that for nonnegative values of 𝑎, the square root of 𝑎 squared is equal to 𝑎. And so the square root of three squared is equal to three. The expression is therefore equal to three multiplied by three multiplied by three or three cubed, which is equal to 27. So filling in the blank, the given expression simplifies to 27.

Let’s now consider another example in which we’ll see how to simplify the quotient of two powers in which the bases are the negatives of one another.

What is the value of negative root three to the sixth power divided by root three to the third power?

The bases in this expression are nearly the same, but one is the negative of the other. We can’t yet apply laws of exponents to simplify this division as the bases aren’t exactly the same. So let’s instead think about how we can alter this expression so that the bases are identical.

In the first term, we have the power of a product because negative root three is equal to negative one multiplied by root three. We can therefore recall the power of a product rule for exponents, which states that a product 𝑎𝑏 to the 𝑛th power is equal to 𝑎 to the 𝑛th power multiplied by 𝑏 to the 𝑛th power. So we can rewrite the first term as negative one to the sixth power multiplied by root three to the sixth power. We can then recall that negative one to any even power is positive one. So in fact, the first term simplifies to root three to the sixth power.

We now have exactly the same base for both parts of the quotient. So we can simplify using the quotient rule for exponents, which tells us that to divide powers of the same base, we subtract the exponents. So root three to the sixth power divided by root three to the third power is root three to the power of six minus three, which is root three cubed. We can express this longhand as root three multiplied by root three multiplied by root three. And then we can group the first two terms in the product together to give root three squared multiplied by root three.

We then recall that for nonnegative real values of 𝑎, the square root of 𝑎 squared is equal to 𝑎. And so the square root of three squared is equal to three. And the expression simplifies to three root three. We found that the value of negative root three to the sixth power divided by root three to the third power is three root three.

Each of the examples we’ve considered so far have involved only positive exponents. The rules, however, hold whether the exponents are positive or negative. We need to recall some further key properties to allow us to work with zero and negative exponents, both of which apply when the base is nonzero. Firstly, any nonzero real base to the power of zero is equal to one. Secondly, we recall that a negative exponent defines a reciprocal. 𝑎 to the power of negative 𝑛 is equal to one over 𝑎 to the power of 𝑛.

In our next example, we’re going to apply the law for negative exponents to a problem in which the bases are fractional. Before we do this, we can use the second rule to write down a further property. This is called the power of a quotient rule for negative exponents. And it states that for nonzero values of 𝑎 and 𝑏, 𝑎 over 𝑏 to the negative 𝑛 is equal to 𝑏 over 𝑎 to the power of 𝑛. We can briefly demonstrate why this rule holds. Applying the law for negative exponents to the expression 𝑎 over 𝑏 to the negative 𝑛 gives one over 𝑎 over 𝑏 to the 𝑛.

Applying the power of a quotient rule in the denominator, this is equivalent to one over 𝑎 to the 𝑛th power over 𝑏 to the 𝑛th power. But we know that dividing by a quotient is equivalent to multiplying by its reciprocal. So this is equivalent to one multiplied by 𝑏 to the 𝑛th power over 𝑎 to the 𝑛th power. And then applying the power of a quotient rule in reverse, this is equal to 𝑏 over 𝑎 to the 𝑛th power. Let’s now see how we can apply this rule in an example.

For 𝑎 equal to 15 over four and 𝑏 equal to five over two, evaluate 𝑎 squared 𝑏 to the negative three.

Let’s begin by substituting the numeric values of 𝑎 and 𝑏 into the given expression. And we have 15 over four squared multiplied by five over two to the negative three. To simplify the second term in this product, we can recall the power of a quotient rule for negative exponents. This states that for 𝑎 and 𝑏 not equal to zero, 𝑎 over 𝑏 to the negative 𝑛 is equal to 𝑏 over 𝑎 to the power of 𝑛. So leaving the first term in the product unchanged, the second term is equal to two-fifths to the power of three.

We then recall the power of the quotient rule, which states that 𝑎 over 𝑏 to the 𝑛th power is equal to 𝑎 to the 𝑛th power over 𝑏 to the 𝑛th power. So applying this rule to each term, we have 15 squared over four squared multiplied by two cubed over five cubed. We can then write the expression out longhand and cancel common factors in the numerator and denominator of the quotient. When we do, we’re left with three multiplied by three in the numerator over two multiplied by five in the denominator, which is equal to nine over 10. So we found that when 𝑎 is equal to 15 over four and 𝑏 is equal to five over two, 𝑎 squared 𝑏 to the negative three is equal to nine-tenths.

The final thing we’re going to consider is how we can solve equations in which either the bases or the exponents are the same. Suppose first we have the equation two to the power of 𝑥 is equal to two to the power of four. As the bases on each side of the equation are the same, the only way these two expressions can be equal is if the exponents are also equal. So equating the exponents, we have the solution 𝑥 is equal to four. In a similar way, suppose we have the equation 𝑦 to the fourth power is equal to three to the fourth power.

As this time the exponents of the two expressions are the same, we may think that the bases must be the same too. But in fact, it’s a little bit more complicated than that because it depends on whether the power is even or odd. Three to the fourth power is equal to 81, but so is negative three to the fourth power. So 𝑦 could be equal to three, but it could also be equal to negative three. We would express this by saying the absolute value of 𝑦 is equal to three. If however the exponent is an odd integer, so suppose we have the equation 𝑧 cubed equals three cubed, then we don’t have this same issue. Three cubed is equal to 27, but negative three cubed is equal to negative 27. In this case, we can say that if the exponents are the same, then the bases must also be the same.

We can formalize each of these processes for solving equations using the following rules. Firstly, if 𝑎 to the 𝑚th power equals 𝑎 to the 𝑛th power, where 𝑎 is a real number but not negative one, zero, or one, then 𝑚 must be equal to 𝑛. And secondly, if 𝑎 to the 𝑛th power is equal to 𝑏 to the 𝑛th power, then 𝑎 is equal to 𝑏 when 𝑛 is an odd integer and the absolute value of 𝑎 is equal to the absolute value of 𝑏 when 𝑛 is an even integer. In our final example, we’ll demonstrate how we can use these laws to solve an equation in which the unknown is in the exponent.

Find the value of 𝑥 in the equation 16 multiplied by two to the power of nine minus 𝑥 is equal to two to the power of 𝑥 minus one squared.

To find the value of 𝑥, we can use laws of exponents. But in order to do this, we need to first express every term in the equation as a power of the same base. We have two to the power of nine minus 𝑥 and two to the power of 𝑥 minus one all squared. So let’s think about how we can rewrite the term 16. Well, 16 is two to the fourth power. So replacing 16 with two to the fourth power, we have the entire equation in terms of the same base.

Now we can start to apply some laws of exponents. On the left-hand side, we have a product of powers of the same base. So we can apply the product rule for exponents, which states that to multiply powers of the same base, we add the exponents. The left-hand side is therefore equivalent to two to the power of four plus nine minus 𝑥. On the right-hand side, we have a power raised to another power. So we can simplify this using the power rule of exponents, which states that in this instance, we multiply the powers together. So the right-hand side becomes two to the power of two multiplied by 𝑥 minus one. Simplifying the exponent on each side, we have two to the power of 13 minus 𝑥 equals two to the power of two 𝑥 minus two.

Now as the bases on each side of the equation are the same, it must also be true that the exponents are the same. So equating the exponents gives the equation 13 minus 𝑥 equals two 𝑥 minus two. We now solve this equation for 𝑥. Adding both two and 𝑥 to each side gives 15 equals three 𝑥. And then, dividing both sides of the equation by three, we find that 𝑥 is equal to five. So the value of 𝑥 in the given equation is five.

Let’s now summarize the key points from this video. We can use the laws of exponents to simplify powers with real bases. For real values of 𝑎 and 𝑏 and integer values of 𝑚 and 𝑛, the product rule for exponents, the quotient rule for exponents, the power rule for exponents, the power of a product rule, and the power of a quotient rule all apply. We also introduced the power of a quotient rule for negative exponents. For nonzero values of 𝑎 and 𝑏, 𝑎 over 𝑏 to the negative 𝑛 is equal to 𝑏 over 𝑎 to the power of 𝑛. We also saw some key rules for working with squares and square roots. For nonnegative real values of 𝑎, the square root of 𝑎 squared is equal to 𝑎 and the square root of 𝑎 squared is also equal to 𝑎.

To solve simple exponential equations with real bases, we can use the following rules when either the bases or exponents are equal. If 𝑎 to the 𝑚 equals 𝑎 to the 𝑛, where 𝑎 is a real number but not negative one, zero, or one, then 𝑚 must be equal to 𝑛. And if the exponents are the same, so if 𝑎 to the 𝑛 equals 𝑏 to the 𝑛, then 𝑎 is equal to 𝑏 when 𝑛 is an odd integer and the absolute value of 𝑎 is equal to the absolute value of 𝑏 when 𝑛 is an even integer.

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