Question Video: Identifying the Acidic Radical That Can Be Detected with the Lead(II) Acetate Test Chemistry

Filter paper wetted with a lead(II) acetate solution is used as a part of the primary test for an acidic radical. What is this acidic radical?

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Video Transcript

Filter paper wetted with a lead(II) acetate solution is used as a part of the primary test for an acidic radical. What is this acidic radical? (A) Sulfate, SO4 2−; (B) nitrite, NO2 1−; (C) sulfide, S2−; (D) phosphate, PO4 3−; or (E) thiosulfate, S2O3 2−.

In chemistry, when we want to know if a solution or solid contains certain compounds, we perform what is known as a qualitative test. Typically, the qualitative tests are chemical reactions that create highly visible indications for the presence of acidic radicals. The term acidic radical refers to a negatively charged ion or anion.

This question deals specifically with a qualitative test using a lead(II) acetate solution on filter paper. An unknown solid can be tested using dilute hydrochloric acid. If the solid contains sulfide anions, they react with the hydrogen ions from the acid to form hydrogen sulfide, a foul-smelling gas. This gas has no color, and we cannot safely smell it for detection. Because of this, we must use another reaction to test for the presence of hydrogen sulfide. We can do this using a filter paper soaked in lead(II) acetate.

When exposed to the hydrogen sulfide gas, the lead(II) acetate will react. This reaction results in the formation of a black precipitate, lead(II) sulfide, on the filter paper. So, if this color change is witnessed, we can say that hydrogen sulfide gas has been produced. We can also indirectly say that sulfide anions were present in our original sample. It is worth mentioning that to confirm the presence of sulfide anions, we would need to perform a secondary confirmatory test that involves another series of reactions.

So, which acidic radical can be detected in a primary test using filter paper wetted with lead(II) acetate? The correct answer is answer choice (C) sulfide, S2−.

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