### Video Transcript

Find the point π΄ on the π₯-axis
and π΅ on the π¦-axis such that three over two, negative five over two is the
midpoint of π΄π΅.

So in this question, weβre told the
midpoint of the line because weβre told that itβs three over two, negative five over
two. And this, coupled with a formula
for the midpoint of a line, will help us to find the point π΄ and the point π΅. So the formula for the midpoint of
a line is π₯ one plus π₯ two over two, π¦ one plus π¦ two over two. And that gives us our π₯- and
π¦-coordinates respectively. And this is where π₯ one, π¦ one
and π₯ two, π¦ two are the coordinates of two different points, so the two endpoints
on our line.

In our question, the two endpoints
are π΄ and π΅. So therefore, weβre gonna have π₯
one, π¦ one for point π΄ and π₯ two, π¦ two for point π΅. Before we even need to use our
midpoint formula, what we can do is find two of our coordinates just from the
information in the question. The first one is one of our
π΄-coordinates. And thatβs because it tells us that
the point π΄ is on the π₯-axis. Well, if we mark any point on the
π₯-axis, we can see that its π¦-coordinate is going to be zero. So therefore, we can say that π¦
one is going to be zero and the π¦-coordinate of π΄ is going to be zero.

And similarly, if we look at point
π΅, it tells us that point π΅ is on the π¦-axis. So therefore, if we mark any point
on the π¦-axis, we can see at this point the π₯-coordinate is going to be zero. So therefore, π₯ two is zero and
the π₯-coordinate of point π΅ is zero. So great, weβve got two of our
coordinates already. So now, what we need to do is find
our missing values, so π₯ one and π¦ two.

First of all, weβre gonna find π₯
one. And weβre gonna to do that using
the first part of our formula, the π₯-coordinate portion which tells us that π₯ one
plus π₯ two over two will give us our π₯-coordinate. Well, we know that the
π₯-coordinate is three over two. So therefore, we know that π₯ one
plus zero, and thatβs because π₯ two is zero, all divided by two is equal to three
over two. Well, therefore, we have π₯ one
over two equals three over two. So we can multiply each side of our
equation by two. And when we do this, we get π₯ one
is equal to three. So therefore, we found the first of
our missing coordinates.

Okay, so now we can move on to π¦
two. And letβs find that. Well, to find π¦ two, what weβre
gonna use is the second part of our formula. And thatβs π¦ one plus π¦ two over
two. And this is because this tells us
our π¦-coordinate. And we know that the π¦-coordinate
of the midpoint is negative five over two. So therefore, we know that zero,
and thatβs zero because π¦ one is equal to zero, plus π¦ two over two is equal to
negative five over two. So once again, what we do is
multiply each side of the equation by two. And when we do that, we get π¦ two
is equal to negative five. So therefore, we found our other
missing coordinates.

So from this, what we can say is
that the point π΄ on the π₯-axis and the point π΅ on the π¦-axis, such that three
over two, negative five over two is the midpoint of π΄π΅, are three, zero and zero,
negative five, respectively.