Question Video: Finding the Set of Zeros of a Linear Function | Nagwa Question Video: Finding the Set of Zeros of a Linear Function | Nagwa

Question Video: Finding the Set of Zeros of a Linear Function Mathematics • Third Year of Preparatory School

Find the set of zeros of the function 𝑓(𝑥) = 𝑥³ − 4𝑥² − 25𝑥 + 100 = 0, where all three zeros take integer values.

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Video Transcript

Find the set of zeros of the function 𝑓 of 𝑥 equals 𝑥 cubed minus four 𝑥 squared minus 25𝑥 plus 100 equals zero, where all three zeros take integer values.

To find the zeros of a function, we set the function equal to zero. So we have 𝑥 cubed minus four 𝑥 squared minus 25𝑥 plus 100 equals zero. We are given that all three zeros of the function take integer values. So we may be able to factorize the polynomial via the grouping method. In the first two terms, we have a common factor of 𝑥 squared, which we can factorize with 𝑥 minus four. We also have a common factor of negative 25 in the last two terms. And this also factorizes with the term 𝑥 minus four. Therefore, we have a common factor of 𝑥 minus four between the first two terms and the last two terms. We can therefore factorize the polynomial to give 𝑥 minus four times 𝑥 squared minus 25. 25 is a square number, five squared. So, in this second term, we have a difference of two squares.

Recall that when we have an expression in the form 𝑎 squared minus 𝑏 squared, it can be factorized as 𝑎 minus 𝑏 times 𝑎 plus 𝑏. We can therefore factorize 𝑥 squared minus 25 as 𝑥 minus five times 𝑥 plus five. We now have a product of three binomials linear in 𝑥. So we cannot factorize any further. Since we have a product of three terms equal to zero, at least one of them must be equal to zero itself. Therefore, either 𝑥 minus four equals zero, 𝑥 minus five equals zero, or 𝑥 plus five equals zero. And we can solve these three equations for 𝑥 to give 𝑥 equals four, 𝑥 equals five, and 𝑥 equals negative five. Therefore, the set of zeros of 𝑓 is negative five, four, and five.

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