Question Video: Finding the Number of Elements of a Cartesian Product of a Given Set by Itself | Nagwa Question Video: Finding the Number of Elements of a Cartesian Product of a Given Set by Itself | Nagwa

# Question Video: Finding the Number of Elements of a Cartesian Product of a Given Set by Itself Mathematics • Third Year of Preparatory School

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If π = {0, 2, β13, 14, 15}, find π(πΒ²).

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### Video Transcript

If π equals zero, two, negative 13, 14, 15, find π, the number of elements in π squared.

The set π is made up of five values. If we were going to multiply this set by itself, π times π, we would need to do something like this. Each term in the set must be multiplied by itself and then by the other four terms.

Letβs consider zero. It must be multiplied by itself and then by two, negative 13, 14, and 15. If we followed this procedure for each element of π, we would end up with a set of 25 elements. This question is only asking how many elements would be in this set. There would be 25.

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