Question Video: Finding the Length of a Side in a Right Triangle Using Trigonometric Identities | Nagwa Question Video: Finding the Length of a Side in a Right Triangle Using Trigonometric Identities | Nagwa

Question Video: Finding the Length of a Side in a Right Triangle Using Trigonometric Identities Mathematics • Third Year of Preparatory School

The circumference of a circle with a center 𝑀 is 259 and the line segment 𝑍𝑌 is tangent at 𝑌. Calculate the length of the line segment 𝑍𝑌 to the nearest hundredth.

04:32

Video Transcript

The circumference of a circle with a center 𝑀 is 259 and the line segment 𝑍𝑌 is tangent at 𝑌. Calculate the length of the line segment 𝑍𝑌 to the nearest hundredth.

Well, the first thing we do with this type of question is mark on any values we know. Well, the first thing we’re told is that the circumference of the circle is 259. Well, we know that there’s a formula for the circumference of a circle. And this is that 𝑐 is equal to 𝜋𝑑. But how is this gonna be useful? Well, if we take a look at our sketch, we can see that 𝑋𝑌 is gonna be the diameter and that’s because we know that the center is 𝑀. So, therefore, what we can do is use our formula and the information we know to work out the diameter. Because what we can say is that 259 is gonna be equal to 𝜋𝑑. Well, this is going to give us that 259 divided by 𝜋 is equal to 𝑑. So that’s our diameter.

Well, what we could have done now is calculated what this is. But we leave this in this form for accuracy because it prevents any rounding issues later in the problem. Okay, so we have this side marked on, or we’ve got 𝑋𝑌 — our diameter — marked on. But is there anything else we can do? Well, we’re told that the line segment 𝑍𝑌 is tangent at 𝑌. But what does this mean? Well, we know that if a line is tangent to a circle at a point, then at this point a right angle is gonna be formed between the tangent and the radius, which I’ve shown here. Once again, we know that 𝑀𝑌 is a radius because we know that 𝑀 is the center of the circle.

Okay, great. So, now, what do we need to do? Well, in the question, we can see that what we’re trying to do is find the length of the line segment 𝑍𝑌. Well, what we, in fact, have now is a right triangle, where we have one side, then a side we want to find, and then we’ve got an angle. So, therefore, because we have these things and because we’ve got this angle, what we’re gonna use is our trigonometric ratios to help us solve this problem and find the line segment 𝑍𝑌. Well, the first thing we do if we’re gonna use trigonometry is label our triangle.

So we’ve got the hypotenuse, which is the longest side opposite the right angle. Then, we’ve got the opposite, which is opposite the angle that we’ve been given. And then we’ve got the adjacent, which is between the right angle and the angle we’ve been given. And also, it’s adjacent to the angle we’ve been given. Well, whenever we’re solving a trigonometry problem, we’ve got a stepped approach. Our first step was label, which we’ve done. And the second step is to decide which one of our trigonometric ratios we’re going to use.

And to help us do that, what we have is a memory aid, which is SOHCAHTOA. And what this tells us is that sine of an angle is equal to the opposite divided by the hypotenuse. The cosine of an angle is equal to the adjacent divided by the hypotenuse. And the tangent of an angle is equal to the opposite divided by adjacent. Well, if we take a look at our problem, we can see that we know the opposite and we want to find the adjacent because that’s the line segment 𝑍𝑌. So therefore, if we look at our SOHCAHTOA, we can see the 𝑂 and 𝐴, so the opposite and the adjacent, are part of the tangent ratio. So, therefore, we’re gonna use tan 𝜃 is equal to the opposite divided by the adjacent.

So now, step three or the next step is to substitute in the values we’ve got. So when we do that, what we’re gonna get is that tan 30 is equal to 259 over 𝜋 over 𝐴, which is our adjacent. So now, what we’re gonna do to rearrange and make 𝐴 the subject is multiply by 𝐴 and then divide by tan 30. So now, what we’re gonna do is put it in the calculator because we’ve got the 𝐴, which is our line segment 𝑍𝑌, is equal to 259 over 𝜋 divided by tan 30. So, therefore, we know that the adjacent 𝐴 is gonna be equal to 142.79418 etc. But we haven’t finished here cause what we’re looking for is the answer to the nearest hundredth.

Well, if we’re looking to the nearest hundredth, it’s gonna be the second decimal place because the first decimal place is the tenth. So, we’ve drawn a line here. And then, the number to the right of this is gonna be the deciding number. And because it’s less than five, then what we’re gonna do is round down. So, therefore, what we can say is that the length of the line segment 𝑍𝑌 is 142.79 and that’s to two decimal places or the nearest hundredth.

Join Nagwa Classes

Attend live sessions on Nagwa Classes to boost your learning with guidance and advice from an expert teacher!

  • Interactive Sessions
  • Chat & Messaging
  • Realistic Exam Questions

Nagwa uses cookies to ensure you get the best experience on our website. Learn more about our Privacy Policy