### Video Transcript

A horse was pulling a wooden block
along a section of horizontal ground. The pulling force of the horse was
22 kilogram-weight which was acting on the block at an angle of 60 degrees to the
vertical. Given that the block was moving
uniformly, determine the magnitude of friction acting on the block.

We will begin by sketching the
block and the forces acting on it. We are told that there is a pulling
force of 22 kilogram-weight acting at an angle of 60 degrees to the vertical, as
shown. We are told that the block was
moving uniformly. Therefore, its acceleration is zero
meters per second squared. And we are asked to calculate the
magnitude of the friction acting on the block; we will call this π
π. And we know that this will act
horizontally in the direction against the motion.

In order to calculate this force,
weβll need to resolve horizontally and as such weβll need to work out the horizontal
component of the 22 kilogram-weight force. One way of doing this is using our
knowledge of right angle trigonometry. By drawing a right triangle, we see
that the 22 kilogram-weight force is the hypotenuse and the horizontal component of
this force is the opposite. We know that the sin of any angle
π is equal to the opposite over the hypotenuse. This means that the sin of 60
degrees is equal to π₯ over 22. We know that the sin of 60 degrees
is equal to root three over two. And we can then multiply through by
22, giving us π₯ is equal to 11 root three. The horizontal component of the
pulling force is 11 root three kilogram-weight.

We can now resolve horizontally
using Newtonβs second law. This states that the sum of our
forces is equal to the mass multiplied by the acceleration. If we let the positive direction be
the direction of motion, the sum of our forces is 11 root three minus π
π. And since we have already
established that there is no acceleration, this is equal to zero. We can then add the frictional
force π
π to both sides of our equation.

The magnitude of the friction
acting on the block is therefore equal to 11 root three kilogram-weight.