Question Video: Solving Equations Involving Exponents | Nagwa Question Video: Solving Equations Involving Exponents | Nagwa

Question Video: Solving Equations Involving Exponents Mathematics • Second Year of Secondary School

Find the value of 𝑥 for which 81^(𝑥 + 5) = (1/3)^𝑥.

02:25

Video Transcript

Find the value of 𝑥 for which 81 to the power of 𝑥 plus five is equal to one-third to the power of 𝑥.

We’ve been given an equation involving two terms with variable exponents. We have 81 to the power of 𝑥 plus five and one-third to the power of 𝑥. The key to answering this question is to spot that both 81 and one-third can be written as powers of three. In fact, 81 is three to the fourth power. And since a negative exponent gives us that reciprocal, one-third is three to the power of negative one. This means we can rewrite 81 to the power of 𝑥 plus five as three to the fourth power to the power of 𝑥 plus five.

And this is really useful because we know that when we have an expression raised to a power and then we raise that to another power, we simply multiply those powers or those exponents. So 𝑥 to the power of 𝑎 to the power of 𝑏 is 𝑥 to the power of 𝑎 times 𝑏. So three to the power of four to the power of 𝑥 plus five is the same as three to the power of four times 𝑥 plus five.

Let’s repeat this process with one-third to the power of 𝑥. It’s three to the power of negative one times 𝑥. And then we’re going to multiply those exponents. Well, negative one times 𝑥 is negative 𝑥. So one-third to the power of 𝑥 is the same as three to the power of negative 𝑥.

And so we can rewrite our original equation as three to the power of four times 𝑥 plus five equals three to the power of negative 𝑥. And this is great because we now have two expressions with equal bases. So for these two expressions to be equal, their powers themselves must also be equal. That is, four times 𝑥 plus five must be equal to negative 𝑥. Let’s distribute the parentheses on the left-hand side, and we’ll then be able to solve for 𝑥.

When we do, we get four 𝑥 plus 20 equals negative 𝑥. Let’s subtract four 𝑥 from both sides. So 20 is equal to negative five 𝑥. To solve for 𝑥, we now need to divide through by negative five. So 𝑥 is 20 divided by negative five. And that of course is equal to negative four. The value of 𝑥 then for which 81 to the power of 𝑥 plus five is equal to one-third to the power of 𝑥 is negative four.

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