Question Video: Calculating the Strength of the Magnetic Field at a Distance from a Current-Carrying Wire | Nagwa Question Video: Calculating the Strength of the Magnetic Field at a Distance from a Current-Carrying Wire | Nagwa

Question Video: Calculating the Strength of the Magnetic Field at a Distance from a Current-Carrying Wire Physics • Third Year of Secondary School

A long wire is carrying a direct current. As a result, a magnetic field of 8.0 × 10⁻⁵ T can be measured at a perpendicular distance of 13 cm from the wire. What would the strength of the magnetic field be at a perpendicular distance of 26 cm from the wire? Give your answer in scientific notation to one decimal place.

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Video Transcript

A long wire is carrying a direct current. As a result, a magnetic field of 8.0 times 10 to the negative fifth teslas can be measured at a perpendicular distance of 13 centimeters from the wire. What would the strength of the magnetic field be at a perpendicular distance of 26 centimeters from the wire? Give your answer in scientific notation to one decimal place.

Alright, so let’s say that this is our long wire that’s carrying a direct current. As a result of this current, we’re told that if we go out a perpendicular distance from the wire of 13 centimeters, then we can measure a magnetic field strength of 8.0 times 10 to the negative fifth teslas. Building on this, our question asks, if we were to travel out from our wire a perpendicular distance of 26 centimeters, then what would be the strength of the magnetic field at that distance from the wire?

So then we know the strength of the magnetic field created by this wire a distance of 13 centimeters away from it. We can call that field strength 𝐵 13. And it’s equal to 8.0 times 10 to the negative fifth teslas. And what we want to do is solve for the field strength a distance of 26 centimeters from the wire, what we’ll call 𝐵 26.

Now, because these two magnetic field strengths, 𝐵 13 and 𝐵 26, are due to the same current in the same wire, we can be helped by recalling that, in general, the magnetic field created by a current-carrying straight wire is equal to the constant 𝜇 naught, the permeability of free space, times the current in the wire divided by two times 𝜋 times the distance from the wire at which we’re measuring the field. For our purposes, the most interesting aspect of this equation is how the magnetic field strength 𝐵 varies with the distance from the wire 𝑑.

We can see that 𝐵 varies as one over 𝑑 or, in other words, is inversely proportional to it. This means, for example, that if we were to double our perpendicular distance from a given wire, then we would cut in half the strength of the magnetic field at that point. And in fact, that’s exactly what we’re doing here in this example. We started out a perpendicular distance of 13 centimeters from our wire. We can consider that our original distance. And then we doubled that to 26 centimeters. By this relationship here, we can see that when we double the distance 𝑑, we cut 𝐵 in half.

And so, given that this is the magnetic field strength a distance of 13 centimeters from our wire, we can expect that 𝐵 26 will be one-half of this. And the reason we know that is that 𝐵 26 is the strength of the magnetic field at twice the distance from the wire, where 𝐵 13 was measured. In doubling our distance, we’ve halved our field strength. And so, in scientific notation, to one decimal place, 𝐵 26 is 4.0 times 10 to the negative fifth teslas. This is the strength of the magnetic field a distance of 26 centimeters from the wire.

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