Video Transcript
Find the limit of negative four
over π₯ squared plus five over π₯ plus eight as π₯ approaches infinity.
We have a limit as π₯
approaches infinity here, but all the normal rules of limits still apply. For example, the limit of a sum
of functions is equal to the sum of the limits. And so, we can split our limit
up into three. Itβs equal to the limit of
negative four over π₯ squared as π₯ approaches infinity plus the limit of five
over π₯ as π₯ approaches infinity plus the limit of eight as π₯ approaches
infinity.
What can we say about this
limit? Well, we know that the limit of
a constant πΎ, as π₯ approaches some number π, is just πΎ. And as for the previous limit
law, this holds true, even if π isnβt a real number but is infinity or negative
infinity. The value of this last limit is
just eight.
What about the other two
limits? We can use the fact that the
limit of a constant multiple of a function is that constant multiple of the
limit of the function. The first limit is, therefore,
negative four times the limit of one over π₯ squared as π₯ approaches
infinity. And the second is five times
the limit of one over π₯ as π₯ approaches infinity. And finally, we add the
eight.
Now, the limit of the
reciprocal function one over π₯, as π₯ approaches infinity, is something we
should know. Its value is zero. But how about the limit of one
over π₯ squared as π₯ approaches infinity? Well, we can use the fact that
the limit of a power of a function is that power of the limit of the
function. This limit is the limit of the
reciprocal function one over π₯ squared, as one over π₯ squared equals one over
π₯ all squared. And by our limit law, this is
the limit of one over π₯ as π₯ approaches infinity all squared. This limit is known to be
zero. And so, our limit, the limit of
one over π₯ squared as π₯ approaches infinity, is also zero.
We can generalize in that you
get another limit law that the limit of one over π₯ to the power of π, as π₯
approaches infinity, is zero, at least if π is greater than zero. Our original limit is,
therefore, negative four times zero plus five times zero plus eight, which is,
of course, just eight.