Video Transcript
Find the area of the shaded
region.
So essentially, weβll want the area
of the two pink triangles. And the area of a triangle is
one-half times the base times the height. Now we know the height of the
triangles. Itβs six π₯. However, we know the basis
completely together to be 15π₯ plus five. So letβs maybe find a different
way, because the 15π₯ plus five weβre not sure how to split them up.
Instead, letβs think of this as an
entire rectangle area and then taking away that white triangle, this one. And this will give us the area of
the shaded region. The area of a rectangle is length
times width, and the area of a triangle is one-half times the base times the
height. So we know the length and the width
of the rectangle. So we need to take 15π₯ plus five
times six π₯.
And then the triangle, if we will
look at this upside down, it might be a little easier. But we will use this as the base,
the 15π₯ plus five, and the height of that triangle will be six π₯. So one-half base times height would
be one-half times 15π₯ plus five times six π₯.
Letβs go ahead and rewrite it down
here so we have more room, because we need to distribute. 15π₯ times six π₯ is 90π₯ squared,
and five times six π₯ would be 30π₯. Bring down our subtraction
sign. We can go ahead and take one-half
times six, which is three. So we can think of this is as 15π₯
plus five times three π₯. 15π₯ times three π₯ is 45π₯
squared.
Now it is important to put a
bracket out front. That way, we recognise the minus
sign β thatβs pink β will need to be distributed to everything in the blue. And five times three π₯ would be
15π₯. So now we need to distribute this
negative sign. So we actually have minus 45π₯
squared minus 15π₯.
Now we can combine like terms. 90π₯ squared minus 45π₯ squared
would be 45π₯ squared. 30π₯ minus 15π₯ would be 15π₯. Therefore, 45π₯ squared plus 15π₯
will be the area of the shaded region. It may also be written as 15π₯
times three π₯ plus one, because we could take out a greatest common factor of 15π₯
from both terms. Either answer will probably be
fine.