Question Video: Relating the Currents and Resistances of a Galvanometer and a Shunt Connected in Parallel | Nagwa Question Video: Relating the Currents and Resistances of a Galvanometer and a Shunt Connected in Parallel | Nagwa

Question Video: Relating the Currents and Resistances of a Galvanometer and a Shunt Connected in Parallel Physics • Third Year of Secondary School

A galvanometer and a shunt resistor are connected in parallel to form an ammeter. The resistance of the shunt is 𝑅_S and the resistance of the galvanometer is 𝑅_G. The current in the shunt is 𝐼_S and the current in the galvanometer is 𝐼_G. Which of the following correctly relates these values? [A] 𝑅_(S)/𝑅_(G) = 𝐼_(G)/𝐼_(S) [B] 𝑅_(S)/𝑅_(G) = 𝐼_(S)/𝐼_(G)

02:43

Video Transcript

A galvanometer and a shunt resistor are connected in parallel to form an ammeter. The resistance of the shunt is 𝑅 𝑆 and the resistance of the galvanometer is 𝑅 𝐺. The current in the shunt is 𝐼 𝑆 and the current in the galvanometer is 𝐼 𝐺. Which of the following correctly relates these values? (A) 𝑅 𝑆 over 𝑅 𝐺 equals 𝐼 𝐺 over 𝐼 𝑆. (B) 𝑅 𝑆 over 𝑅 𝐺 equals 𝐼 𝑆 over 𝐼 𝐺.

To help us think about this question, let’s consider the form of an ammeter. When electric charge flows through an ammeter, it passes through two parallel branches, one with a galvanometer and another with a shunt resistor. If we want to relate the individual values of the resistance and current at the resistor and galvanometer to each other, we’ll have to recall Ohm’s law. Let’s choose a form that relates everything to potential difference 𝑉.

Ohm’s law can be written as 𝑉 equals 𝐼𝑅, where 𝑉 is the potential difference, 𝐼 is the current, and 𝑅 is the resistance. If we specifically use Ohm’s law across the shunt resistor, we find that 𝑉 𝑆 equals 𝐼 𝑆 𝑅 𝑆. Similarly, using Ohm’s law across the galvanometer, we get 𝑉 𝐺 equals 𝐼 𝐺 𝑅 𝐺.

Now, looking back at our diagram, let’s recall that parallel branches in circuits will have the same potential difference across each branch. This means that when we connect a shunt resistor in parallel with the galvanometer, the potential difference across the shunt resistor will be equal to the potential difference across the galvanometer. This means that 𝑉 𝑆 equals 𝑉 𝐺.

We can now substitute these specific potential differences with their relations to current and resistance. And we find that 𝐼 𝑆 𝑅 𝑆 equals 𝐼 𝐺 𝑅 𝐺. From here, dividing both sides by 𝑅 𝐺, we get 𝐼 𝑆 𝑅 𝑆 divided by 𝑅 𝐺 equals 𝐼 𝐺. And then dividing both sides by 𝐼 𝑆, we get 𝑅 𝑆 divided by 𝑅 𝐺 equals 𝐼 𝐺 divided by 𝐼 𝑆.

So now we have an equation that relates the resistances of the shunt and galvanometer with their currents. And we can see that this answer corresponds with option (A). Therefore, option (A) is the correct answer that relates these values together.

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