Question Video: Determining the Number of Atoms of Vanadium in a Vanadium Oxide from the Percentage Composition | Nagwa Question Video: Determining the Number of Atoms of Vanadium in a Vanadium Oxide from the Percentage Composition | Nagwa

Question Video: Determining the Number of Atoms of Vanadium in a Vanadium Oxide from the Percentage Composition Chemistry • First Year of Secondary School

A vanadium compound has the molecular formula V_(𝑥) O₃, where 𝑥 is a whole number. If the percentage by mass of V in V_(𝑥) O₃ is 68%, what is the value of 𝑥? [O = 16 g/mol, V = 51 g/mol]

03:37

Video Transcript

A vanadium compound has the molecular formula V 𝑥 O 3, where 𝑥 is a whole number. If the percentage by mass of V in V 𝑥 O 3 is 68 percent, what is the value of 𝑥? The molar mass of oxygen is 16 grams per mole and vanadium, 51 grams per mole.

To calculate the percentage by mass, if we assume that we’re calculating the percentage by mass of element A present in substance B, then we need to divide the mass of element A by the mass of substance B and multiply it by 100 percent. More specifically for this example, element A will be V, vanadium, and substance B will be V 𝑥 O 3, vanadium oxide. So to find the percent by mass of vanadium in vanadium oxide, we need to divide the mass of vanadium, making sure to include the subscript value, which in this case is 𝑥, by the mass of vanadium oxide and multiply by 100 percent.

We have been given the percentage by mass of vanadium in vanadium oxide in the question. It is 68 percent. To find the mass of vanadium, we can use the molar mass. The molar mass of vanadium is 51 grams per mole, so one mole of vanadium is 51 grams. Therefore, 𝑥 moles of vanadium will be 𝑥 times 51 grams. To find the mass of vanadium oxide, we need to use the molar masses of oxygen and vanadium. We have already established that 𝑥 moles of vanadium is 𝑥 times 51 grams. The molar mass of oxygen is 16 grams per mole, so one mole of oxygen is 16 grams.

We have three equivalents in the molecular formula of vanadium oxide, so we need to multiply three by 16 grams. Adding 𝑥 times 51 grams and three times 16 grams will give us the mass of one mole of vanadium oxide. We then need to multiply this by 100 percent. Since we’re trying to find the value of 𝑥, we need to make 𝑥 the subject. But first, let’s simplify this a bit. We can divide both sides of the equation by 100 percent to give us 0.68 equals 𝑥 times 51 grams divided by 𝑥 times 51 grams plus 48 grams.

If we multiply both sides of the equation by 𝑥 times 51 grams plus 48 grams and then multiply the contents of the parentheses by 0.68, then we get 34.68𝑥 grams plus 32.64 grams equals 51𝑥 grams. We need to make 𝑥 the subject. So we need to subtract 34.68𝑥 grams from both sides of the equation. So 32.64 grams equals 16.32𝑥 grams. If we divide both sides of the equation by 16.32 grams, we find that 𝑥 equals two. So the answer to the question “If the percentage by mass of vanadium in vanadium oxide is 68 percent, what is the value of 𝑥?” is two.

Join Nagwa Classes

Attend live sessions on Nagwa Classes to boost your learning with guidance and advice from an expert teacher!

  • Interactive Sessions
  • Chat & Messaging
  • Realistic Exam Questions

Nagwa uses cookies to ensure you get the best experience on our website. Learn more about our Privacy Policy