### Video Transcript

Find the range of the function π
of π₯ is equal to π₯ plus five when π₯ is in the closed interval from negative five
to negative one and π of π₯ is equal to negative π₯ plus three if π₯ is in the
left-open, right-closed interval from negative one to three.

In this question, weβre asked to
find the range of a given piecewise-defined function. And we can start by recalling the
range of a function is the set of all outputs of that function given the domain of
that function, or the set of inputs. And we recall when we graph a
function, the π¦-coordinate of any point on the curve represents the output value of
that function for that given input value of π₯. For example, because our function
passes through the point negative one, four, we know that π evaluated at negative
one is equal to four. Four is a possible output of our
function. We can even confirm this from our
piecewise definition of π of π₯.

We can see that negative one lies
in the first subdomain of our function. So when we evaluate π at negative
one, we get negative one plus five, which is equal to four. We want to find all of the possible
output values of this function. We can see from the graph the
highest possible output value is four. Similarly, we can find the lowest
possible output value of our function. The lowest possible output value of
our function is zero, where itβs worth pointing out because our graph does not have
hollow dots at the endpoints on either side, this confirms our function is defined
when π₯ is equal to negative five and when π₯ is equal to three. We can also see this from the
subdomains of our function.

So the highest output of our
function is four, and the lowest output of our function is zero. And we can see that there are
values of π₯ for every input in between. And the set of all values from zero
to four, including the endpoints, is the closed interval from zero to four. Therefore, we were able to show the
range of the function π of π₯ is equal to π₯ plus five when π₯ is in the closed
interval from negative five to negative one and π of π₯ is equal to negative π₯
plus three when π₯ is in the left-open, right-closed interval from negative one to
three is the closed interval from zero to four.