# Question Video: Finding the Missing Terms in an Algebraic Equation Involving the Distributive Property Mathematics

Complete οΌΏ(οΌΏ β ππβ΄) = 3πβ΄πβΈ β πΒ²πβΈ.

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### Video Transcript

Complete the blanks in this equation. Something multiplied by something minus ππ to the fourth equals three π to the forth π to the eighth minus π squared π to the eighth.

The distributive property is being used here. But itβs our job to figure out what exactly is being distributed. Our missing value here was distributed across this subtraction problem to produce three π to the fourth π to the eighth minus π squared π to the eighth.

Letβs focus our energy on these two pieces. How would we go from π times π to the fourth to π squared π to the eighth? To figure out what was being multiplied here, we can use division. We divide π squared π to the eighth by π times π to the forth. When we do that, our π squared becomes π to the first power, and our π to the eighth becomes π to the fourth power. This is the value weβll plug in here, π times π to the fourth. Itβs the value being distributed across this problem.

Now we need to focus on our last missing term. We need to know what π times π to the fourth was multiplied by to produce three π to the fourth π to the eighth. We can use the same process here. We can use division to find out what was being multiplied. Weβll divide three π to the fourth π to the eighth by ππ to the fourth. The three canβt be divided, so we keep that. Our π to the fourth becomes π cubed, and our π to the eighth becomes π to the fourth. This means the final missing value would be three π cubed π to the fourth.

Our two missing pieces were π times π to the fourth, three times π cubed times π to the fourth.