Question Video: Using Probabilities in a Venn Diagram to Calculate Conditional Probabilities and Decide Whether Events Are Independent | Nagwa Question Video: Using Probabilities in a Venn Diagram to Calculate Conditional Probabilities and Decide Whether Events Are Independent | Nagwa

Question Video: Using Probabilities in a Venn Diagram to Calculate Conditional Probabilities and Decide Whether Events Are Independent Statistics • Third Year of Secondary School

The Venn diagram shows the probabilities of events 𝐴 and 𝐵 occurring or NOT occurring in different combinations. Calculate the value of 𝑥. Hence, Calculate 𝑃(𝐴). Calculate 𝑃(𝐴 | 𝐵). Are 𝐴 and 𝐵 independent events?

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Video Transcript

The Venn diagram shows the probabilities of events 𝐴 and 𝐵 occurring or not occurring in different combinations. Now, there are four parts to this question. Calculate the value of 𝑥. Hence, calculate the probability of 𝐴. Calculate the probability of 𝐴 given 𝐵. And finally, are 𝐴 and 𝐵 independent events?

So what we’re gonna do is start with this first part, which is calculate the value of 𝑥. Well, what we know about a Venn diagram like this is that when we’re looking at probability, all the values must add together to equal one. So, therefore, we have one-seventh plus four-sevenths plus two over 21 plus 𝑥 equals one.

So now if we want to add our fractions, what we want to do is have a common denominator. So we can convert one-seventh to three over 21 and four-sevenths to 12 over 21. So then we’ve got three over 21 plus 12 over 21 plus two over 21 plus 𝑥 equals one. So, therefore, we’ve got 17 over 21 plus 𝑥 equals one. Well, to make one, what we need is 21 over 21. So, therefore, 𝑥 must be equal to four over 21.

Okay, great, so now what we can do is move on to the second part of the question. Hence, calculate the probability of 𝐴. Well, the probability of 𝐴 is given by anything inside the oval that we have here, which is 𝐴. So we’ve got one-seventh and four over 21. So, therefore, the probability of 𝐴 is gonna be equal to a seventh plus four over 21. Well, again, what we need is a common denominator. So we’re gonna make 21 our common denominator. And we’ve already seen that one-seventh is equal to three over 21. So, therefore, we can say the probability of 𝐴 is equal to three over 21 plus four over 21. So then if we add our numerators, we’re gonna get the probability of 𝐴 is equal to seven over 21.

Okay, great, have we finished there? Well, no, because what we can do is we can actually cancel down or simplify our fraction. And we can do this by dividing both the numerator and denominator by seven. So, when we do that, we get a third. So, therefore, we can say that the probability of 𝐴 is a third.

So now what we can do is move on to the next part of the question, where we’re asked to calculate the probability of 𝐴 given 𝐵. So what this means is the probability of event 𝐴 occurring given that event 𝐵 occurs. So what this question asks is conditional probability, because we’re asked to calculate the probability of event 𝐴 occurring given that event 𝐵 occurs. So, if we look at the Venn diagram, what we’ve got here is in pink of circle where event 𝐵 occurs. And then what we want to know is the probability that 𝐴 occurs, which I’ve shaded in here orange, given these conditions.

Well, we’ve got a formula to help us solve this part of the problem because we know that the probability of 𝐴 given 𝐵 is equal to the probability of 𝐴 intersection 𝐵 divided by the probability of 𝐵. Well, we already know the probability of 𝐴 intersection 𝐵 because this was 𝑥 in the first part of the question, because what this means is the probability of 𝐴 and 𝐵. And we can work out the probability of 𝐵 because this is equal to four over seven plus four over 21, which is gonna be equal to 12 over 21 plus four over 21, which is equal to 16 over 21.

So now we have both parts of our formula because we know that the probability of 𝐴 intersection 𝐵 is four over 21 and the probability of 𝐵 is 16 over 21. So, therefore, we know the probability of 𝐴 given 𝐵 is four over 21 divided by 16 over 21. Well, if we remember how we divide fractions, then what we do is we keep the first fraction the same. We change the divide to multiply, and then we flip the second fraction or find the reciprocal of the second fraction. So what we’ve got is four over 21 multiplied by 21 over 16.

So then what we could do is just multiply the numerators and denominators. But to make it easier, what we can do is a bit of simplifying first. And first of all, we can divide both the numerators and denominators by 21 and then divide the numerator and denominators by four. And what we’re left with is one multiplied by one over one multiplied by four. So, therefore, we can say that the probability of 𝐴 given 𝐵 is gonna be equal to a quarter.

Okay, great, so now what we can do is move on to the final part of the question. Are 𝐴 and 𝐵 independent events? Well, what we know is that two events are independent if the probability of 𝐴 and 𝐵, or the probability of 𝐴 intersection 𝐵, is equal to the probability of 𝐴 multiplied by the probability of 𝐵.

Well, we’ve already calculated the probability of 𝐴 and the probability of 𝐵 earlier on in our problem. So, therefore, what we can do is multiply these together. So, when we do that, what we’re gonna get is one over three multiplied by 16 over 21, which is gonna give us 16 over 63.

Well, now, what we want to do is compare this to the probability of 𝐴 intersection 𝐵. Well, we know that the probability of 𝐴 intersection 𝐵 is four over 21, because we worked this out in the first part of the question. Well, we can convert four over 21 into something over 63, and that’s gonna be 12 over 63. And we do that by multiplying the numerator and denominator by three. So, therefore, if we compare the probability of 𝐴 multiplied by the probability of 𝐵 and the probability of 𝐴 intersection 𝐵, we can see that 16 over 63 is not equal to 12 over 63. So, therefore, we can say that events 𝐴 and 𝐵 are not independent.

So, therefore, for a quick recap, we can say that the value of 𝑥 is four over 21, the probability of 𝐴 is a third, the probability of 𝐴 given 𝐵 is one-quarter, and no, events 𝐴 and 𝐵 are not independent.

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