### Video Transcript

The sum of the roots of the
equation four π₯ squared plus ππ₯ minus four equals zero is negative one. Find the value of π and the
solution set of the equation.

So, weβre looking, first of all, to
find the value of π, which is a missing coefficient in this quadratic equation. Itβs the coefficient of π₯. Weβre going to need to use the
quadratic formula to find expressions for the roots of this equation, which will be
in terms of π. And we recall that, for the general
quadratic equation ππ₯ squared plus ππ₯ plus π equals zero, its roots are given
by π₯ equals negative π plus or minus the square root of π squared minus four ππ
all over two π.

Letβs determine the values of π,
π, and π for this quadratic equation then, which is in the correct form with all
the terms on the same side. The value of π is the coefficient
of π₯ squared. So π is equal to four. The value of π is the coefficient
of π₯. So π is equal to this unknown
value π. And the value of π is the constant
term, so π is equal to negative four. Substituting into the quadratic
formula then, we have that π₯ is equal to negative π plus or minus the square root
of π squared minus four multiplied by four multiplied by negative four all over two
multiplied by four. In the denominator, two times four
is eight. And within the square root, four
times four times negative four is negative 64. And subtracting negative 64 is the
same as adding 64. So, we have negative π plus or
minus the square root of π squared plus 64 all over eight.

Now, weβre told this key piece of
information, that the sum of the roots of this equation is negative one. Adding the expressions for our two
roots then, and we have the equation on the screen. Now, as both of these fractions
have a common denominator of eight, we can actually combine to a single
fraction. And what we notice is that thereβs
actually quite a lot of simplification. We have plus the square root of π
squared plus 64, and then minus the square root of π squared plus 64. So, these two terms will cancel
each other out. Weβre left with the far simpler
equation negative two π over eight is equal to negative one, which we can solve by
multiplying by eight and dividing by negative two to give π equals four.

In fact, this is illustrative of a
general and really useful result. When we added our two roots
together, the part under the square root canceled out due to them having different
signs. So, what we were left with, the
contribution from each root to the sum, was just negative π over two π. We therefore summed two lots of
this, giving negative two π over two π, which simplified to negative π over
π. In our case, we found that π
equals four. So, the value of π in our
quadratic equation is four. And so, negative π over π gives
negative four over four, which is negative one, the correct sum for the roots. What this has shown though is that,
in general, the sum of the roots of a quadratic equation is equal to negative π
over π. And we can quote this as a general
result.

Now that we know the value of π,
we need to determine the values of π₯. We have negative four plus or minus
the square root of four squared plus 64 over eight. We can simplify the surd here. The square root of 80 is equal to
four root five. And then dividing through by a
common factor of four gives our simplified solutions as negative one plus or minus
the square root of five over two. So, weβve completed the
problem. The value of π is four, and the
solution set of the equation in surd form is negative one minus root five over two,
negative one plus root five over two.