# Video: Differentiating Root Functions

Convert the rectangular equation 𝑥² + 𝑦² = 25 to parametric form.

01:53

### Video Transcript

Convert the rectangular equation 𝑥 squared plus 𝑦 squared equals 25 to parametric form.

Let’s begin by recalling what we actually know about this equation. We know that a circle whose centre is at the origin and whose radius is 𝑟 can be given by the Cartesian equation 𝑥 squared plus 𝑦 squared equals 𝑟 squared. By rewriting our rectangular equation as 𝑥 squared plus 𝑦 squared equals five squared, we see that we have a circle whose centre is at the origin and whose radius is five units. And so, I’ve sketched that on the 𝑥𝑦-plane, as shown.

We’re looking to convert this equation to parametric form. So we know that a pair of parametric equations describe the 𝑥- and 𝑦-coordinates in terms of a third parameter, 𝑡. So let’s pick a general point 𝑥, 𝑦. I’m going to choose this one in the first quadrant. We can drop in a right triangle, whose height is 𝑦 units and whose width is 𝑥 units. And then, we can label the included angle 𝑡. Since the radius of the circle is five units, we know that the hypotenuse of our triangle is five. Then, using standard conventions, we label the sides of our triangle. We have the adjacent; that’s 𝑥. We have the opposite; that’s 𝑦. We have the hypotenuse; that’s five.

We also know that in rectangular trigonometry, sin 𝜃 is equal to the opposite divided by the hypotenuse and cos 𝜃 is equal to the adjacent over the hypotenuse. So we can say that sin 𝑡 equals 𝑦 over five and cos 𝑡 is equal to 𝑥 over five. We can multiply through by five for both of our equations. And we find that 𝑦 is equal to five sin 𝑡 and 𝑥 equals five cos 𝑡. So for any point in our circle, the 𝑦-coordinate is given by five sin of 𝑡 and the 𝑥-coordinate is given by five cos of 𝑡. Now moving in a counterclockwise direction from the positive horizontal axis, we see that as 𝑥 increases from zero, it generates our corresponding 𝑥- and 𝑦-coordinates. Then, our equations are 𝑥 equals five cos 𝑡 and 𝑦 equals five sin 𝑡.