In this video, we are going to look at the trigonometric ratios: sine, cosine, and
tangent, which are the names given to the ratios that exist between the different pairs of sides
in right-angled triangle.
So, let’s begin by looking at the right-angled triangle on the screen here and to
start off with we need to be familiar with the names that are used for the sides in a
right-angled triangle. Now you should have already be familiar with the name hypotenuse, which is the
name given to the longest side of a right-angled triangle — the side which is opposite the right
angle — and you may perhaps have met that before in the Pythagorean theorem.
The other two sides of a right-angled triangle also have particular names and
their names are in relation to the angle that we’re interested in. So in this right-angled
triangle here, I’ve labeled one of the other two angles — the ones that aren’t right angles- I’ve
labeled one of them as 𝜃, so the names of the sides that in relation to this angle 𝜃. The first label is the opposite. And just like the hypotenuse is opposite the
right angle, the opposite side is the one opposite this angle 𝜃. So that would be this side here.
The name that we give to the final side — the third side — is the adjacent. And that side is adjacent or next to both these angles 𝜃 and the right angle. It’s
between those two; that’s how we recognize which of the sides is the adjacent. So you need to be familiar with these three labels: the opposite, the adjacent, and
the hypotenuse. And you need to be comfortable identifying which side is which in various
different right-angled triangles.
So the three trigonometric ratios that we’re interested in are the ratios
between the different pairs of the sides of the right-angled triangle. The first one that we’re
going to look at has the name sine. Now for a particular angle 𝜃, this sine ratio is the ratio between the opposite and
the hypotenuse. So its definition is that sine of the angle 𝜃 is equal to the opposite divided
by the hypotenuse, whatever the lengths of those two sides are. The second ratio is given the name cosine or often abbreviated to cos, and this
is the ratio between the adjacent and the hypotenuse. So it is defined as the cosine of the angle 𝜃 is equal to the adjacent divided
by the hypotenuse. The final ratio is called tangent, often abbreviated to tan, and this is the ratio
between the opposite and the adjacent sides. So its definition is the tangent of the angle 𝜃 is equal to opposite divided
So that’s how these three ratios are defined. And what’s important is that these
ratios for a particular angle 𝜃, they are fixed no matter how big I choose to draw the triangle.
And therefore no matter what the lengths of the opposite, the adjacent, and the hypotenuse are
for a particular angle 𝜃, the values of these three ratios will always be the same. So if I were to extend this triangle, but still keeping the angle 𝜃 constant, then
the value of this sine ratio would be the same whether I use the opposite and the hypotenuse
as they’re labeled in that solid triangle. Or whether I use the opposite and the hypotenuse as they are now marked in red in
the larger triangle. In both cases, when I do the opposite divided by the hypotenuse, I will get
the same value for this ratio. And of course the same thing is true for cosine and for tangent as well.
Now to help you remember the definitions of sine, cosine, and tangent and which
sides were involved, there is a little acronym that you can use to help. And so what we do is we take the first letter of each of those words. So sin
𝜃 is equal to opposite over hypotenuse; so that gives us SOH, S, O, H. Cos is equal to the
adjacent over hypotenuse; that gives us CAH and so on. So SOH, CAH, TOA, if you remember that, then
you’ll be able to remember the definitions of sine, cosine, and tangent more easily. If you wanted to convince yourself that these ratios are in fact constant for a
fixed angle 𝜃, you could do your own investigation. So like the one I’ve started on the screen,
you could draw out a triangle, measure these sides as accurately as possible, and calculate the
ratios. And then continue to a medium triangle and a larger triangle and convince yourself that
the ratios do remain the same.
So let’s look at how we can use this to answer some questions. The first question
we’re given a diagram of a right-angled triangle and we’re asked to write down the value of
cos 𝜃. So for me when I’m answering any problem to do with trigonometry, the first step for
me is always to label the three sides of the triangle in the problem with their labels, so the
opposite, the adjacent, and the hypotenuse. So I’ve just used the first letter of those words here. Remember the hypotenuse is
opposite the right angle, the opposite is opposite the angle 𝜃, and the adjacent is between 𝜃
and the right angle. Now we’re asked about cos of 𝜃, so we need to recall the definition of cos of 𝜃.
And if you remember SOH, CAH, TOA. Well, CAH is adjacent and hypotenuse. So the definition of cos 𝜃 is that the adjacent divided by the hypotenuse.
What I need to do then is just write down what this ratio is for this
particular triangle. So I need to replace the adjacent and the hypotenuse with their values in
this example. So looking at the triangle then, the adjacent is twelve centimeters. So I’m gonna have cos
𝜃 is equal to twelve over- and the hypotenuse looking at the diagram, that’s thirteen. So I have
that cosine of 𝜃 — cos 𝜃 — is equal to twelve over thirteen. So all I needed to do in this question was recall the definition of cos and then
write down the ratio using the values that is specific to this question.
Okay, our second question we’re given another right-angled triangle, and the angle
that we’re interested in is labeled 𝛼 this time rather than 𝜃. And the question asks us to
write down the value of sine of 𝛼. So step one, as in the previous question, first of all, I’m just gonna label
each of these three sides as the opposite, the adjacent, and the hypotenuse. Next, I need to recall what the definition of sine is. So SOH, sine is opposite
divided by hypotenuse.
So looking at the diagram, I can see that I know the hypotenuse; it’s ten millimeters. But I
don’t actually know what the opposite is; that length hasn’t been given to me in the diagram. But I need to know in order to write down this sine ratio. So there’s a little
bit of work that I need to recall in order to work this out, and it’s the Pythagorean theorem.
Because remember the Pythagorean theorem tells us about the relationship that exists between
the three sides in a right-angled triangle. And what the Pythagorean theorem enables me to do is calculate the length of the
third side if I know both of the other two. And in this case I do; I can see they’re ten
millimeters and six millimeters.
Now the Pythagorean theorem, you often see it written as 𝑎 squared plus 𝑏 squared
is equal to 𝑐 squared. But remember what the theorem actually tells us is that if you take the
two shorter sides of a right-angled triangle — so that’s 𝑎 and 𝑏 — and if you square them and add
them together, then it gives you the same result as if you square the longest side, the
hypotenuse. So I can use the Pythagorean theorem to work out the length of this third side.
Now I’m not gonna call it 𝑜 because that might be confused with zero. So we’ll give it a
different letter; let’s call it 𝑏.
So my working for this part of the question, I’m gonna think that third side
is 𝑏. So what I’m gonna do is I’m gonna write out the Pythagorean theorem, but I’m gonna
replace 𝑎 with six and keep 𝑏 as it is and I’ll replace 𝑐 with ten. So I have six squared plus 𝑏 squared is equal to ten squared. Next, I’m gonna
write down what’s six squared and ten squared are. So I’ve thirty-six plus 𝑏 squared is equal to a hundred. Now we want to solve
this equation for 𝑏, so I’m gonna subtract thirty-six from both sides. So I have 𝑏 squared is equal to sixty-four. And then in order to work out 𝑏, I
need to square root both sides. So I’ll have 𝑏 is equal to the square root of sixty-four, which
is eight. So this tells me then that the length of that third side, which is the opposite,
must be eight millimeters.
Now you may actually have been able to spot that without going through the
formal working out because six, eight, ten is an example of a Pythagorean triple that is a
right-angled triangle, where the lengths of all three sides are integers. And if you knew that and
recognized it, then you could cut down on a little bit of the working out here. Right, the reason we wanted to know the length of this third side is because we
wanted to write down the sine ratio. So remember sine is opposite divided by hypotenuse. And
now I know the opposite is eight millimeters and the hypotenuse is ten millimeters. So this tells me then that sine of 𝛼 must be eight over ten. Now that can be simplified
to four-fifths or we could write it as a decimal. So we have our answer to this question which is that sine of 𝛼 is equal to nought
Okay the final example in this video then, we’re asked to write down the value of
tan 𝜃 in this right-angled triangle here. Now, we’re given the length of all three sides in this particular triangle; we’re
not going to need them. So first step as always, we need to label the three sides: the hypotenuse,
the opposite, and the adjacent. Next, we need to recall what the definition of that tan ratio is. So TOA, tan is
the opposite divided by the adjacent.
So looking at our diagram, we’re gonna be using the opposite which is root two
over two and the adjacent which is a half. So because both of these are fractions, I don’t want to write one over the other
and end up with a fraction that has four layers within it. So I’m gonna write tan 𝜃 is root two
over two divided by a half to start off with.
Now I need to simplify that and there’s a couple of different ways you can think
about this. Dividing by a half is the same as multiplying by two or you can think about when
you divide by a fraction, you invert it — you flip it over — and you multiply instead. Both of those ways of thinking about this would lead me to the same point which
is that tan of 𝜃 is equal to root two over two multiplied by two. Now this two in the
numerator and this two in the denominator are gonna cancel each other out. And therefore I’m left with an answer that tan 𝜃 is equal to root two. So then I’ll leave my answer like that in surd form because of course that’s
exact at the moment whereas if I tried to evaluate it as a decimal, I’d need to do some rounding.
So to summarize then, we’ve defined the three trigonometric ratios: sine, cosine,
and tangent as the ratios between different pairs of sides in a right-angled triangle. We’ve seen how to recognize the difference between sine, cosine, and tangent by
using the acronyms SOH, CAH, TOA. And we’ve seen how to write down the value of each of these
trigonometric ratios from a diagram of a right-angled triangle with different lengths labeled.