In this video, we are going to look at the trigonometric ratios: sine, cosine, and
tangent, which are the names given to the ratios that exist between the different pairs
of sides in right-angled triangle.
So, let’s begin by looking at the right-angled triangle on the screen here. And to start
off with, we need to be familiar with the names that are used for the sides in a
right-angled triangle. Now you should already be familiar with the name hypotenuse,
which is the name given to the longest side of a right-angled triangle — the side which
is opposite the right angle. And you may perhaps have met that before in the
The other two sides of a right-angled triangle also have particular names. And their
names are in relation to the angle that we’re interested in. So in this right-angled
triangle here, I’ve labeled one of the other two angles — the ones that aren’t right
angles — I’ve labeled one of them as 𝜃. So the names of the sides that in relation to
this angle 𝜃. The first label is the opposite. And just like the hypotenuse is opposite
the right angle, the opposite side is the one opposite this angle 𝜃. So that would be
this side here.
The name that we give to the final side, the third side, is the adjacent. And that
side is adjacent or next to both, this angles 𝜃 and the right angle. It’s between those
two. And that’s how we recognize which of the sides is the adjacent. So you need to be
familiar with these three labels: the opposite, the adjacent, and the hypotenuse. And
you need to be comfortable identifying which side is which in various different
So the three trigonometric ratios that we’re interested in are the ratios between the
different pairs of the sides of the right-angled triangle. The first one that we’re
going to look at has the name sine. Now for a particular angle 𝜃, this sine ratio is the
ratio between the opposite and the hypotenuse. So its definition is that sine of the
angle 𝜃 is equal to the opposite divided by the hypotenuse, whatever the lengths of
those two sides are. The second ratio is given the name cosine or often abbreviated to
cos. And this is the ratio between the adjacent and the hypotenuse. So it is defined as
the cosine of the angle 𝜃 is equal to the adjacent divided by the hypotenuse. The final
ratio is called tangent, often abbreviated to tan, and this is the ratio between the
opposite and the adjacent sides. So its definition is that tangent of the angle 𝜃 is
equal to opposite divided by adjacent.
So that’s how these three ratios are defined. And what’s important is that these ratios,
for a particular angle 𝜃, they are fixed no matter how big I choose to draw the
triangle. And therefore, no matter what the lengths of the opposite, the adjacent, and
the hypotenuse are. For a particular angle 𝜃, the values of these three ratios will
always be the same. So if I were to extend this triangle, but still keeping that angle
𝜃 constant, then the value of this sine ratio would be the same, whether I use the
opposite and the hypotenuse as they’re labeled in that solid triangle, or whether I use
the opposite and the hypotenuse as they are now marked in red in the larger triangle. In
both cases, when I do the opposite divided by the hypotenuse, I will get the same value
for this ratio. And of course, the same thing is true for cosine and for tangent as well.
Now to help you remember the definitions of sine, cosine, and tangent and which sides
were involved, there is a little acronym that you can use to help. And so what we do is
we take the first letter of each of those words. So sin 𝜃 is equal to opposite over
hypotenuse. So that gives us SOH, S, O, H. Cos is equal to the adjacent over hypotenuse.
That gives us CAH, and so on. So SOHCAHTOA, if you remember that, then you’ll be able
to remember the definitions of sine, cosine, and tangent more easily. If you wanted to
convince yourself that these ratios are in fact constant for a fixed angle 𝜃, you could
do your own investigation. So like the one I’ve started on the screen, you could draw
out a triangle, measure these sides as accurately as possible, and calculate the ratios.
And then continue to a medium triangle and a larger triangle and convince yourself that
the ratios do remain the same.
So let’s look at how we can use this to answer some questions. The first question, we’re
given a diagram of a right-angled triangle and we’re asked to write down the value of
cos 𝜃. So for me, when I’m answering any problem to do with trigonometry, the first step
for me is always to label the three sides of the triangle in the problem with their
labels, so the opposite, the adjacent, and the hypotenuse. So I’ve just used the first
letter of those words here. Remember the hypotenuse is opposite the right angle, the
opposite is opposite the angle 𝜃, and the adjacent is between 𝜃 and the right angle. Now
we’re asked about cos of 𝜃. So we need to recall the definition of cos of 𝜃. And if you
remember SOHCAHTOA, well CAH is adjacent and hypotenuse. So the definition of cos
𝜃 is that it’s the adjacent divided by the hypotenuse.
What I need to do then is just write down what this ratio is for this particular
triangle. So I need to replace the adjacent and the hypotenuse with their values in this
example. So looking at the triangle then, the adjacent is 12 centimeters. So I’m gonna
have cos 𝜃 is equal to 12 over — and the hypotenuse looking at the diagram, that’s 13 — so
I have that cosine of 𝜃, cos 𝜃, is equal to 12 over 13. So all I needed to do in this
question was recall the definition of cos and then write down the ratio using the values
that are specific to this question.
Okay, our second question, we’re given another right-angled triangle. And the angle that
we’re interested in is labeled 𝛼 this time rather than 𝜃. And the question asked us to
write down the value of sine of 𝛼. So step one, as in the previous question, first of
all, I’m just gonna label each of these three sides as the opposite, the adjacent, and
the hypotenuse. Next, I need to recall what the definition of sine is. So SOH, sine is
opposite divided by hypotenuse.
So looking at the diagram, I can see that I know the hypotenuse. It’s 10 millimeters.
But I don’t actually know what the opposite is. That length hasn’t been given to me in
the diagram. But I need to know in order to write down this sine ratio. So there’s a
little bit of work that I need to recall in order to work this out. And it’s the
Pythagorean theorem. Because remember, the Pythagorean theorem tells us about the
relationship that exists between the three sides in a right-angled triangle. And what
the Pythagorean theorem enables me to do is calculate the length of the third side, if I
know both of the other two. And in this case I do. I can see they’re 10 millimeters and
Now the Pythagorean theorem, you often see it written as 𝑎 squared plus 𝑏 squared is
equal to 𝑐 squared. But remember, what the theorem actually tells us is that if you take
the two shorter sides of a right-angled triangle — so that’s 𝑎 and 𝑏 — and if you square
them and add them together, then it gives you the same result as if you square the
longest side, the hypotenuse. So I can use the Pythagorean theorem to work out the
length of this third side. Now I’m not gonna call it 𝑂 because that might be confused
with zero. So I’m gonna give it a different letter. Let’s call it 𝑏.
So in my working for this part of the question, I’m gonna think of that third side as 𝑏. So
what I’m gonna do is I’m gonna write out the Pythagorean theorem. But I’m gonna replace
𝑎 with six and keep 𝑏 as it is. And I’ll replace 𝑐 with 10. So I have six squared plus
𝑏 squared is equal to 10 squared. Next, I’m gonna write down what’s six squared and 10
squared are. So I’ve 36 plus 𝑏 squared is equal to 100. Now I want to solve this
equation for 𝑏. So I’m gonna subtract 36 from both sides. So I have 𝑏 squared is equal
to 64. And then in order to work out 𝑏, I need to square root both sides. So I’ll have
𝑏 is equal to the square root of 64, which is eight. So this tells me then that the
length of that third side, which is the opposite, must be eight millimeters.
Now you may actually have been able to spot that without going through the formal
working out because six, eight, 10 is an example of a Pythagorean triple. That is a
right-angled triangle, where the lengths of all three sides are integers. And if you
knew that and recognized it, then you could cut down on a little bit of the working out
here. Right, the reason we wanted to know the length of this third side is because we
wanted to write down the sine ratio. So remember, sine is opposite divided by hypotenuse.
And now I know the opposite is eight millimeters and the hypotenuse is 10 millimeters.
So this tells me then that sine of 𝛼 must be eight over 10. Now that can be simplified
to four-fifths. Or, we could write it as a decimal. So we have our answer to this question,
which is that sine of 𝛼 is equal to 0.8.
Okay, the final example in this video then, we’re asked to write down the value of tan
𝜃 in this right-angled triangle here. Now, we’re given the lengths of all three sides in
this particular triangle. We’re not going to need them. So first step as always, we need
to label the three sides: the hypotenuse, the opposite, and the adjacent. Next, we need
to recall what the definition of that tan ratio is. So TOA, tan is the opposite divided
by the adjacent.
So looking at our diagram, we’re gonna be using the opposite which is root two over two
and the adjacent which is a half. So because both of these are fractions, I don’t want
to write one over the other and end up with a fraction that has four layers within it.
So I’m gonna write tan 𝜃 is root two over two divided by a half, to start off with.
Now I need to simplify that. And there’s a couple of different ways you can think about
this. Dividing by a half is the same as multiplying by two. Or, you can think about when
you divide by a fraction, you invert it — you flip it over — and you multiply instead.
Both of those ways of thinking about this would lead me to the same point which is that
tan of 𝜃 is equal to root two over two multiplied by two. Now this two in the numerator
and this two in the denominator are gonna cancel each other out. And therefore, I’m left
with an answer that tan 𝜃 is equal to root two. So I’m gonna leave my answer like that
in surd form because of course, that’s exact at the moment. Whereas, if I tried to evaluate
it as a decimal, I’d need to do some rounding.
So to summarize then, we’ve defined the three trigonometric ratios: sine, cosine, and
tangent as the ratios between different pairs of sides in a right-angled triangle. We’ve
seen how to recognize the difference between sine, cosine, and tangent by using that
acronym SOHCAHTOA. And we’ve seen how to write down the value of each of these
trigonometric ratios from a diagram of a right-angled triangle with different lengths