### Video Transcript

Which of the following geometric
sequences can be summed up to β?

And then, weβre given five
sequences to choose from. We begin by recalling that a
geometric sequence is one which has a common ratio between terms. The πth term of a geometric
sequence is ππ to the power of π minus one, where π is the first term and π is
the common ratio. Now, we can sum a geometric
sequence to β if itβs convergent. And this occurs when the modulus of
π or the absolute value of π, where π is the common ratio, is less than one.

Now, weβre told that all of these
sequences are geometric sequences, and so our job is to find the common ratio. Letβs begin with sequence (A). Thatβs eight times six to the power
of π minus five. Weβre going to need to write this
in this form: π times π to the power of π minus one. And we can use one of our rules for
exponents to do so. We know that when we multiply two
exponential terms which have the same base, we simply add their exponents. And so, we can reverse this and say
that βWell, six to the power of π minus five is the same as six to the power of
negative four times six to the power of π minus one.β Six to the power of negative four,
though, is one over six to the power of four. And so, we can rewrite this as
eight over six to the power of four times six to the power of π minus one.

If we compare this to the general
πth term of a geometric sequence, we see that π, which is the first term in this
sequence, is eight over six to the fourth power. π, however, is six. Now, itβs quite clear to us that
six is not less than one. We can, therefore, say that
sequence (A) is not convergent, and so we cannot sum it up to β.

And so, we move on to sequence
(B). This time, we recall that we can
find the common ratio by dividing any term by the term that precedes it. And so, in this case, we can divide
three twenty-eighths by one twenty-eighth. And since the denominators of these
fractions is the same, thatβs three divided by one, which is three. Once again, three is not less than
one. And so, sequence (B) is not
convergent and cannot be summed to β.

Letβs have a look at sequence (C)
now. Once again, weβll find the common
ratio by dividing the second term by the first. Remember, we would get the same
answer if we divided the third term by the second and so on. One method we have for dividing
fractions is to create a common denominator. Now, if we multiplied 263 by five,
we get 1315. So, 263 is equivalent to one
thousand three hundred and fifteen fifths. And so, we then divide the
numerators. And we find π is equal to negative
789 over 1315. This value for π is between
negative one and one. And so, we can say that the
absolute value of the common ratio in this sequence is less than one. This means itβs convergent and it
can be summed to β.

Letβs just double-check the other
two sequences. By dividing the second term by the
first in sequence (D), we can see that the absolute value of the common ratio is not
less than one, and so it canβt be (D). And in fact, we get the same value
for the common ratio in sequence (E). And so that confirms to us that the
only geometric sequence in this list that can be summed to β is (C).