Lesson: Single-Slit Diffraction High School Physics

Physics

In this lesson, we will learn how to calculate the positions of points of maximum and minimum intensity in diffraction patterns generated by single-slits

Worksheet: 10 Questions

Q1:

Light of wavelength 475 nm passes through a slit 8.25 Ξm in width and falls onto a screen 4.6 cm in front of the slit, producing a diffraction pattern that has its central maximum at a point directly in front of the slit. The angle 𝜃 that light in the diffraction pattern makes with the line passing through the center of the slit and the center of the diffraction pattern is small enough for sin𝜃≃𝜃. What is the width of the central maximum of the pattern? Answer to two significant figures.

Q2:

Light of wavelength 550 nm passes through a slit 7.55 Ξm in width and falls onto a screen 12.5 cm in front of the slit, producing a diffraction pattern that has its central maximum at a point directly in front of the slit. The angle 𝜃 that light in the diffraction pattern makes with the line passing through the center of the slit and the center of the diffraction pattern is small enough for sin𝜃≃𝜃. What is the distance from the central maximum of the diffraction pattern to the first minimum of the pattern?

Q3:

Light of wavelength 𝜆 passing through a narrow slit of width ð‘Ī falls on a screen where a diffraction pattern is produced. Which of the following formulas correctly relates 𝜆 and ð‘Ī to the angle 𝜃 from a line that intersects the center of the slit and the center of the diffraction pattern to a line that intersects the center of the slit and a minimum of the diffraction pattern of order 𝑚?

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