In this lesson, we will learn how to calculate the positions of points of maximum and minimum intensity in diffraction patterns generated by single-slits
Students will be able to
Q1:
Light of wavelength 550 nm passes through a slit 7.55 μm in width and falls onto a screen 12.5 cm in front of the slit, producing a diffraction pattern that has its central maximum at a point directly in front of the slit. The angle 𝜃 that light in the diffraction pattern makes with the line passing through the center of the slit and the center of the diffraction pattern is small enough for sin𝜃≃𝜃. What is the distance from the central maximum of the diffraction pattern to the first minimum of the pattern?
Q2:
Light of wavelength 475 nm passes through a slit 8.25 μm in width and falls onto a screen 4.6 cm in front of the slit, producing a diffraction pattern that has its central maximum at a point directly in front of the slit. The angle 𝜃 that light in the diffraction pattern makes with the line passing through the center of the slit and the center of the diffraction pattern is small enough for sin𝜃≃𝜃. What is the width of the central maximum of the pattern? Answer to two significant figures.
Q3:
Light of wavelength 𝜆 passing through a narrow slit of width 𝑤 falls on a screen where a diffraction pattern is produced. Which of the following formulas correctly relates 𝜆 and 𝑤 to the angle 𝜃 from a line that intersects the center of the slit and the center of the diffraction pattern to a line that intersects the center of the slit and a minimum of the diffraction pattern of order 𝑚?
Nagwa uses cookies to ensure you get the best experience on our website. Learn more about our Privacy Policy.