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In this lesson, we will learn how to find the solution of an equation that has only one root by graphing and verifying the answer algebraically.

Q1:

The graph in the diagram represents the function π ( π₯ ) = 2 π₯ β 7 . Without performing any calculation, use the graph to solve 2 π₯ β 7 = 0 .

Q2:

The graph in the diagram represents the function π ( π₯ ) = β 5 π₯ + 3 2 . Without performing any calculation, use the graph to solve β 5 π₯ + 3 2 = 0 .

Q3:

Consider the equation π¦ = β 2 π₯ β 4 . In the following, find a solution by filling the blank space.

( , 4 ) .

( , β 8 ) .

( , β 6 ) .

These solutions ( π₯ , π¦ ) can be plotted as seen in the figure. What will be true of any other solution plotted in the plane?

Q4:

Which points in the graph represent a solution to the equation π¦ = 2 .

Q5:

Consider the equation π¦ = 2 π₯ + 3 . In the following, find a solution by filling the blank space.

( 3 , ) .

( β 2 , ) .

( 1 , ) .

Q6:

Which points in the graph represent a solution to the equation π₯ = 3 ?

Q7:

Which points in the graph represent a solution to the equation π₯ = β 3 ?

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