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In this lesson, we will learn how to solve a cubic equation written as sum or difference of two cubes.
Q1:
Find the value of π¦ given that ( 2 π¦ β 1 4 ) β 3 6 = 2 8 3 .
Q2:
Given that π₯ β β and β π₯ 1 0 = 1 0 0 π₯ 2 , determine the value of π₯ .
Q3:
Determine the solution set of the equation 3 1 β 6 π₯ = β 2 2 2 π₯ β 6 9 8 3 3 in β .
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