Lesson: Dielectric ConstantPhysics
In this lesson, we will learn how to calculate the capacitance of a capacitor given the dielectric constant of the material separating the capacitor plates.
Sample Question Videos
An air-filled capacitor is made from two flat parallel plates located 1.0 mm apart. The area of each plate is 8.0 cm2.
What is the capacitance of the plates?
What is the capacitance of the plates if the region between the plates is filled with a material whose dielectric constant is 6.0?
A parallel-plate capacitor has square plates that are 8.00 cm on each side and 3.80 mm apart. The space between the plates is completely filled with two square dielectric slabs, each of a side 8.00 cm and 1.90 mm in thickness. One slab is Pyrex glass with a dielectric constant and the other slab is polystyrene with a dielectric constant . If the potential difference between the plates is 86.0 V, find how much electrical energy can be stored in this capacitor.
A parallel-plate capacitor with only air between its plates is charged by connecting the capacitor to a battery. The capacitor is then disconnected from the battery, without any of the charge leaving the plates.
A voltmeter reads 45.0 V when placed across the capacitor. When a dielectric is inserted between the plates, completely filling the space, the voltmeter reads 11.5 V. What is the dielectric constant of the material?
What will the voltmeter read if the dielectric is now pulled out from between the capacitor plates so that dielectric material fills only one-third of the space between the plates?