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In this lesson, we will learn how to calculate the capacitance of a capacitor given the dielectric constant of the material separating the capacitor plates.

Q1:

An air-filled capacitor is made from two flat parallel plates located 1.0 mm apart. The area of each plate is 8.0 cm^{2}.

What is the capacitance of the plates?

What is the capacitance of the plates if the region between the plates is filled with a material whose dielectric constant is 6.0?

Q2:

What is the capacitance of a parallel plate capacitor having plates with a surface area of 4.50 m^{2} and separated by 0.100 mm of Teflon™? The dielectric constant of Teflon™ is 2.10.

Q3:

The dielectric constant of Teflon^{™} is 2.1 A Teflon^{™}-filled, parallel-plate capacitor has a plate area of 50.0 cm^{2}. The spacing between these plates is 0.50 mm. The capacitor is connected to a 200-V battery.

Find the free charge on the capacitor plates.

Find the electrical field in the dielectric.

Find the induced charge on the dielectric’s surfaces.

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