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Lesson: Finding the Center of Gravity of Uniform Rods and Laminas

In this lesson, we will learn how to find the position of the center of gravity (mass) of a standard uniform plane lamina, including a rectangle, a triangle, and a semicircle.

Worksheet: Finding the Center of Gravity of Uniform Rods and Laminas • 14 Questions

Q1:

Where does the centre of gravity of a fine rod, , of uniform density lie?

Aat the midpoint of
Bat point
Cat point

Q2:

A uniform lamina is bounded by the parallelogram . Where does its centre of gravity lie?

Aat the intersection point of the parallelogram’s diagonals
Bat point
Cat point

Q3:

Where does the centre of gravity of a uniform circular disc lie?

Aat the centre of the circle
Bon the circumference
Cat the centre of the radius

Q4:

Where does the centre of gravity of a uniform triangular lamina lie?

Aat the intersection of its medians
Bat the intersection of its diagonals
Cat the intersection of its altitudes

Q5:

A uniform rod of length of 36 cm was bent from point , where , and . The rod was then suspended freely from . Find the tangent of the angle that makes to the horizontal.

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