Lesson: Center of Mass of Laminas
In this lesson, we will learn how to find the position of the center of gravity (mass) of a lamina composed of standard shapes in 2D.
Sample Question Videos
Worksheet: 25 Questions • 1 Video
The given uniform lamina is shaped as a rectangle where , , and such that . The corner is folded over along the line such that the side meets the side as shown in the figure. Find the coordinates of the center of gravity of the lamina in this new shape.
The given figure shows a uniform lamina bounded by a square of side length 4 cm. It is divided into nine congruent squares. If square is cut off, find the coordinates of the center of gravity of the remaining part.
A uniform lamina in the form of an equilateral triangle of side length 24 cm has a mass of 298 g. A mass of 149 g is attached to the lamina at one of the trisection points of as shown in the figure. Determine the coordinates of the system’s center of gravity.