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In this lesson, we will learn how to find the derivatives of trigonometric functions, focusing on derivatives of cotangent, secant, and cosecant functions.
Q1:
Find d d π¦ π₯ if π¦ = β 5 7 π₯ + 9 π₯ s i n s e c 2 2 .
Q2:
Given that π¦ = ( 7 5 π₯ + 3 6 π₯ ) c o t c s c ο± ο§ , find d d π¦ π₯ .
Q3:
If π¦ = 6 π₯ β 7 π₯ t a n c s c 2 , find d d π¦ π₯ at π₯ = 3 π 4 .
Q4:
Find the derivative of the function π¦ = ( π ) c o t s i n 2 .
Q5:
Find d d π¦ π₯ , given that π₯ = π¦ ( 2 π₯ β 5 ) 2 s e c .
Q6:
Find d d π¦ π₯ if π¦ = οΌ 5 π β 3 7 π₯ ο c o t .
Q7:
If π¦ = ( π₯ + 8 π₯ ) ( π₯ β 8 π₯ ) c s c c o t c s c c o t , find π¦ β² .
Q8:
Given that π¦ = 7 π₯ + 2 οΏ 1 β π₯ ο 5 2 c o t , find d d π¦ π₯ .
Q9:
Given that π¦ = 7 3 π₯ 3 π₯ β 4 c o t , find d d π¦ π₯ .
Q10:
If π¦ = 8 5 π₯ β 6 s e c 2 , find d d π¦ π₯ .
Q11:
Given that π¦ = 5 π₯ 4 π₯ 2 c o t , find d d π¦ π₯ .
Q12:
If π¦ = β 1 9 π₯ + 1 8 c s c , find d d π¦ π₯ .
Q13:
Find d d π¦ π₯ , given that π¦ = β 9 6 π₯ β 7 π₯ t a n c s c .
Q14:
If π¦ = π₯ + 9 π₯ s i n s e c , and π₯ = 6 π π§ , find d d π¦ π§ at π§ = 4 .
Q15:
Given that π¦ = β 9 π₯ + 5 3 π₯ 2 2 c o t , find d d π¦ π₯ .
Q16:
Given that π¦ = 3 ( π₯ + 2 ) c s c 2 5 , find d d π¦ π₯ .
Q17:
Given that π¦ = 4 7 ( 8 π₯ ) s e c t a n 2 , find d d π¦ π₯ .
Q18:
Differentiate π¦ = π₯ β 3 π₯ s e c c s c .
Q19:
If π¦ = β β 4 π§ + 9 , and π§ = 6 π₯ s e c , find d d π¦ π₯ at π₯ = π 1 8 .
Q20:
If π¦ = β 9 8 π₯ 8 π₯ t a n s e c , find d d π¦ π₯ .
Q21:
Find for the function .
Q22:
Find d d π¦ π₯ , given that π¦ = ( β 3 5 π₯ + 7 ) c o t 4 .
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