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In this lesson, we will learn how to use integration to find the work done by a variable force.
Q1:
A particle is moving in a straight line under the action of a force given by where the force is measured in newtons and the displacement is measured in metres. Calculate the work done by the force when the particle moves from to .
Q2:
The figure shows the relation between a force ๐น , measured in newtons, acting on a body and the distance ๐ , in metres, travelled by that body. Determine the work done between ๐ = 0 m and ๐ = 1 0 m .
Q3:
A block moves in a straight line under the action of a force ๐น = ๏น 1 2 ๐ + 6 ๐ + ๐ ๏ ๏จ N , where ๐ metres is the displacement of the body from its initial position. The work done by the force in moving the block from ๐ = 0 m to ๐ = 3 m is 34 J. Determine the work done by ๐น in moving the block from ๐ = 3 m to ๐ = 6 m .
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