Lesson Explainer: Solving Quadratic Equations: Taking Square Roots | Nagwa Lesson Explainer: Solving Quadratic Equations: Taking Square Roots | Nagwa

Lesson Explainer: Solving Quadratic Equations: Taking Square Roots Mathematics

Join Nagwa Classes

Attend live Mathematics sessions on Nagwa Classes to learn more about this topic from an expert teacher!

In this explainer, we will learn how to solve quadratic equations with no linear term using the square root property.

Definition: Quadratic Equation

A quadratic equation is an equation of the form 𝑎𝑥+𝑏𝑥+𝑐=0, where 𝑎, 𝑏, and 𝑐 are constants and 𝑎0.

When we solve a quadratic equation, we find the values of 𝑥 for which 𝑎𝑥+𝑏𝑥+𝑐=0. A quadratic equation will have up to two different solutions for 𝑥. In this explainer, we will look at how to solve a simple quadratic which has no linear term, that is, a quadratic equation in the form 𝑎𝑥+𝑐=0.

Let us recall the definition of real numbers and rational and irrational numbers.

Definition: Real Numbers

A real number is a positive or negative number, including those which have decimal places. A real number can be rational or irrational. We can write real numbers as belonging to the set .

Definition: Rational and Irrational Numbers

A rational number is a number which can be written in the form 𝑎𝑏, where 𝑎 and 𝑏 are integers and 𝑏0. We can write rational numbers as belonging to the set .

An irrational number is one which cannot be written in the form 𝑎𝑏, where 𝑎 and 𝑏 are integers.

To begin, let us consider the equation 𝑥=25.

If we wished to solve this for x, we would take the square root of both sides of the equation. We could solve as 𝑥=25, so 𝑥=5. However, since 5×5 would also give an answer of 25, we can indicate the positive and negative roots here as 𝑥=±25.

So, 𝑥=±5.

It is important to remember that the use of ± indicates two solutions, so 𝑥=±5 represents both 𝑥=5 and 𝑥=5.

Let us now look at some examples of solving quadratic equations by taking square roots.

Example 1: Solving a Quadratic Equation by Taking Square Roots

Solve (𝑥+6)=4.

Answer

Starting from (𝑥+6)=4, we take square roots of both sides of the equation. Recall that when taking square roots we need to consider both the positive and the negative roots. Therefore, 𝑥+6=±4=±2.

Subtracting 6 from both sides gives us 𝑥=±26.

Therefore, 𝑥=+26𝑥=26.or

Hence, our answer is 𝑥=4 or 𝑥=8.

Example 2: Solving a Quadratic Equation by Taking Square Roots

Find the solution set of the equation 4𝑥=𝑥9.

Answer

To begin solving this, we first multiply both sides of the equation 4𝑥=𝑥9 by 𝑥, which gives 4=𝑥9.

Next, we multiply both sides by 9, giving us 36=𝑥.

Taking the square root of both sides, considering both the positive and the negative roots, we have ±36=𝑥±6=𝑥.

Therefore, 𝑥=±6 and our answer is the set {6,6}.

Example 3: Solving a Quadratic Equation by Taking Square Roots

Find the solution set of the equation (𝑥5)=100 in .

Answer

We perform the same operations to both sides of the equation to solve for 𝑥. Taking the square root of both sides, considering both the positive and the negative roots, gives us (𝑥5)=100𝑥5=±100𝑥5=±10.

We can now add 5 to both sides to isolate 𝑥, giving us 𝑥=5±10𝑥=510𝑥=5+10.or

Therefore, the solution set is {5,15}.

We will now look at an example where we first need to rearrange the equation to collect terms together, before solving using square roots.

Example 4: Solving a Quadratic Equation by Taking Square Roots

Determine the solution set of the equation 2𝑥+15=𝑥12.

Answer

To begin solving this equation, we collect all the like terms. Subtracting 𝑥 from both sides and then subtracting 15 from both sides give us 2𝑥+15=𝑥123𝑥+12=123𝑥=27.

We can now divide both sides by 3, which gives us 𝑥=9. Taking the square root of both sides, considering both the positive and the negative roots, gives us 𝑥=±9𝑥=±3. Therefore, the solution set is {3,3}.

Let us now look at an example where we can use the square root method to attempt to solve a quadratic but which gives no solutions for 𝑥.

Example 5: Solving a Quadratic Equation by Taking Square Roots

Determine the solution set of the equation 44𝑥+9=0, given that 𝑥.

Answer

We can solve this by performing the same operations to both sides of the equation to solve for 𝑥.

Subtracting 9 from both sides of the equation and then dividing by 44 give us 44𝑥+9=044𝑥=9𝑥=944.

We can now take the square root of both sides, considering both the positive and the negative roots, which gives us 𝑥=±944.

However, neither 𝑥=944 nor 944 gives us a real solution, since each takes the square root of a negative value. Therefore, the solution set of the equation is the null set: 𝜙.

In this example, we correctly followed the square root method, but there are no real solutions for 𝑥. If we consider the graph of the function 𝑓(𝑥)=44𝑥+9, having no solutions for 𝑥 simply means that the graph would not pass through the 𝑥-axis.

Key Points

  • We can use the square root method to solve a quadratic equation when the quadratic has no terms in 𝑥.
  • We can use the square root method by following the steps below.
    • Collect the 𝑥-terms together, and collect the constant terms on the other side of the equation.
    • Take the square root of both sides of the equation.
  • It is important to remember that when taking a square rootwe must consider both the positive and the negative values of the roots. Using the ± sign is a useful way to indicate these two values.

Join Nagwa Classes

Attend live sessions on Nagwa Classes to boost your learning with guidance and advice from an expert teacher!

  • Interactive Sessions
  • Chat & Messaging
  • Realistic Exam Questions

Nagwa uses cookies to ensure you get the best experience on our website. Learn more about our Privacy Policy