# Lesson Explainer: Euler’s Number (e) as a Limit Mathematics

In this explainer, we will learn how to use the definition of (Euler’s number) to evaluate some special limits.

Euler’s number () is very useful, and arises in many different branches of mathematics including the calculation of compound interest, optimization problems, calculus, and in the definition of the function representing the standard normal probability distribution.

The number may have originally been found when searching for an exponential function that differentiates into itself. However, we can also find Euler’s number by using limits, and this is what we will explore in this explainer.

To define Euler’s number as a limit, let us first recall some information about this number:

1. and is the inverse function of .
2. If , then .
3. If , then .
4. is continuous across its entire domain.

We will use the second result to generate our limit result by using the definition of a derivative from first principles. The third result is found by substituting into the second result.

The definition of a derivative from first principles on at tells us

Replacing in this limit with and using the fact that , we have

Since , this simplifies to

Using the power rule for logarithms, we can express this limit as

Remember, we know this limit is equal to and we already know that . This means we have shown that

Inside this limit, we are taking the natural logarithm, which is a continuous function. We also know that the limit is convergent, and we can use these two facts to take the natural logarithm function outside of the limit, giving us

We can then simplify this further by writing both sides of this equation as exponents of : where we use the fact that the exponential function and natural logarithm functions are inverses and .

This is our first limit result and we can immediately see its use. If we were to try and evaluate the limit directly, we would get the following indeterminate forms:

Limits that cannot be evaluated directly, but can be expressed in this form, can be evaluated in terms of Euler’s number, .

Before we move on, there is one more limit result that we can show directly from the previous one. Substituting into our limit result above gives us

However, we now have a limit involving both and and we want this written entirely in terms of . Since , when approaches 0, must also approach 0. This could be the case if approached either positive or negative infinity, or even oscillated between the two, which means we cannot state which specific value is approaching in our limit.

We can solve this problem by recalling that is convergent, so both its left and right limits at 0 must be equal to the value of this limit, that is, . We will use the right-hand limit:

Now, as approaches 0 from the right, will be approaching positive infinity.

This gives us our second limit result:

We can summarize the results we have just shown.

### Definition: Euler’s Number as a Limit

Let us see some examples of how we can use these two results to evaluate limits that we could not before.

Determine .

### Answer

We could first try to evaluate this limit directly. Our limit has approaching infinity, which means that the denominator of is growing without bound, while the numerator remains constant, so is approaching 0. This means the expression inside our parentheses is approaching 1. However, our exponent () is approaching infinity as approaches infinity.

So, we get which is an indeterminate form. This means we are going to need to try some other method to evaluate our limit.

We notice that the limit we have been given is very similar to one that expresses the value of Euler’s number:

The difference between the two limit expressions is that the one we were given has an exponent of rather than . We can use the laws of exponents to re-express it as follows:

Before we can substitute Euler’s number into the limit expression, we need to move the exponent of 4 outside the limit. Provided the new limit exists, we can use the power rule for limits to achieve this:

The limit inside our exponent exists because it is just our limit result for Euler’s number . So, we use our limit result and replace the limit inside the parentheses with , giving us

Our next example shows how we can use our other limit result to help us evaluate a limit.

Determine .

### Answer

Since we are asked to evaluate a limit, we could begin by attempting to do this directly. As approaches 0, the expression inside our parentheses approaches 1 and the magnitude of our exponent is growing without bound. This is an indeterminate form, specifically , so we will need to try another method.

We can see that our limit is similar to one of our limit results involving Euler’s number, which is

So, we can try using this result to help us evaluate our limit.

To do this, we want our exponent to be the same as that of the limit result, which is . To do this, we will start by using our laws of exponents to rewrite our limit: where we reorder the terms inside our parentheses and use the fact that .

At this point, we want to use our limit result involving Euler’s number; however, we first need to take our exponent outside of our limit altogether and to do that we need to use the power rule for limits.

This tells us we can take the exponent outside of the limit provided our new limit exists.

In our case, we have and we know that this is true because the limit inside our parentheses is exactly the same as the limit result involving Euler’s number. Substituting this limit being equal to , we get

It is not always possible to directly use our limit results for Euler’s number . We may have to use other tools such as polynomial division, factoring, or substitution. However, the basic premise is the same, we take a limit we are unable to evaluate and write it in a form for , which we can use then our limit results to evaluate.

Determine .

### Answer

We are asked to evaluate a limit that we could attempt to evaluate directly. Thus, as approaches , the expression inside our parentheses approaches 1 and the exponent is growing without bound. Hence, we have

This is an indeterminate form, so we will need to try another method to evaluate this limit.

This limit is similar to one of the limit results involving Euler’s number, so we can try using this result to help us evaluate our limit. We have a lot of choices in how to go about this.

We are going to try and write this limit in a form where we can use

However, it is also possible to use

Usually, one of the limit results ends up being easier than the other and it can be very difficult to tell which limit result to use just by looking at the question, so if we get stuck using one result, we can always try using the other limit that is in the form with exponent .

To write our limit in this form, we will want to use a substitution. We would like inside our parentheses, so we use the substitution

We can rearrange this substitution to find in terms of so that

Multiplying this through by 5, we then have

By using this substitution, we can rewrite our limit as

However, this is the limit as approaches infinity and we want to know what happens in terms of , so we will need to look at our substitution. As approaches infinity, approaches 0, and since , we must also have that approaches 0.

This gives us

Now, we use one of the laws of exponents:

Finally, we apply the power rule for limits: which we know we can do in this case because the resulting limit is our limit result involving Euler’s number.

All we need to do now is substitute this limit for and rearrange, so that finally we have

In our next example, we will consider the limit of a rational function raised to a linear exponent.

Determine .

### Answer

We could try evaluating this limit directly. Inside our parentheses, we have a rational function, and we know that as approaches , we can see what happens by looking at the quotient of the leading terms in our rational function. Since this is equal to 1, the limit of our rational function is also 1. However, our exponent is growing without bound, so we have which is an indeterminate form. We will therefore need to try another method to evaluate this limit.

Instead, let us try and evaluate this by using a limit result involving Euler’s number:

We will begin by rewriting our rational function:

If we compare the two limits, we see we will need to use a substitution. We want inside our parentheses, so we use the substitution

We see when approaches infinity that is approaching 0, so must also approach infinity.

Before we use this substitution, we also need to rearrange to find in terms of , which we can do as follows.

We take the reciprocal of both sides of our substitution, giving us

Then, we multiply through by 8 and add 4 to both sides:

We can now use this substitution to rewrite our limit:

We want to use our limit result, but we first need our exponent to be . To do this, we are first going to need to use the laws of exponents combined with the product rule for limits so that

To use the product rule for limits, we need the limit of both factors to exist. We will show in our working that both of these limits exist.

We can evaluate one of these limits directly:

Next, to evaluate our other limit, we use the laws of exponents and the power rule for limits, and this is true provided this limit exists, which we know it does because it is our previous limit result. This means we can replace this limit with Euler’s constant :

Hence, we have shown

We can also use these results to solve limits involving more complicated functions.

Determine .

### Answer

We could try evaluating this limit directly. Inside our parentheses, we have a continuous function, so we can just substitute . However, our exponent is growing without bound, so we have which is an indeterminate form, so we will need to try another method to evaluate this limit.

Instead, let us try and evaluate this by using a limit result involving Euler’s number, that is,

In order to compare this with the limit we are asked to find, we will need to manipulate the expression inside our parentheses into the form . To do this, we begin by substituting

We know that as approaches 0, will approach 0 by direct substitution, so must also approach 0. Also, by taking the reciprocal of both sides of our substitution and rearranging, we have

Using all of this, we can rewrite our limit as

We can then evaluate this limit by using the laws of exponents and the power rule for limits to obtain the required exponent of :

Of course, this is provided that the limit inside our parentheses exists, which as we know it does, since

Finally, we can use our limit result to evaluate the limit inside our parentheses as Euler’s constant:

Hence, we were able to show

Let us finish by recapping some of the basic points of this explainer.

### Key Points

• We found and proved two useful limit results involving Euler’s number:
• We may use these results to evaluate limits that give indeterminate forms by direct substitution or evaluation.
• In order to use these results, we may sometimes need to manipulate our limit using techniques such as polynomial division, substitution, or factoring.

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