In this explainer, we will learn how to find the equation of a circle using its center and a given point or the radius and vice versa.

Let us first recall the precise definition of a circle in mathematical terms.

### Definition: Circle

A circle is the locus of points equidistant from a given point, called the *center* of the circle. This fixed distance
between any point of the circle and its center is the *radius* of the circle.

In other words, a circle is the set of all points, and only those, that are at a given distance from its center.

We note that although a circle can easily be plotted on the -plane, it cannot be described as a function of the form since any one element of the domain can (generally) be associated with two elements of the range. In other words, we can always find two points on the circle that have the same -coordinate.

However, there does exist a relationship between the - and -coordinates of all points
on the circle: this is the **equation of a circle**. To understand this equation, let us first of all consider the most basic
form of a circle: a circle that is centered at the origin of the coordinate plane.

This circle is the locus of points equidistant from the origin. The distance from any point on the circle to the origin is thus equal to the radius of the circle, . The relationship between the - and -coordinates of all the points on the circle can then be found by forming a right triangle as shown in the diagram below, where the hypotenuse is a radius of the circle.

Applying the Pythagorean theorem to this triangle, we find

This expression applies to any point on the circle. The absolute values can be removed here since , for any value of . This leads to the following definition.

### Definition: Equation of a Circle Centered at the Origin

A circle with center and radius is described by the equation

As one might expect, this equation can be extended to circles with any given center. Specifically, if we consider a circle of radius centered at point , this is all the points that are a distance from . If we consider a general point on the circle, we can form a right triangle between the center and this point in the same way as before, where the hypotenuse is the radius of the circle and the horizontal and vertical lengths are and respectively.

Using the Pythagorean theorem on this triangle, we find

Once again, using the fact that for any , we can rewrite this without the absolute values, leading to the following definition for the equation.

### Definition: Equation of a Circle (Standard Form)

A circle with center and radius is described by the equation

An equation of this form is known as the *standard form* of the equation of a circle.

Let us consider how we can apply this equation to find the equation of a circle.

### Example 1: Writing the Standard Form of a Circleβs Equation given Its Center and Radius

Write the equation of a circle with center and radius 9.

### Answer

Recall that the standard form for the equation of a circle is given by where is the center of the circle and is the radius.

In this example, we have been given that the center is , so and . We have also been given that the radius is 9, so , and from this, we can get . Substituting these values in the formula gives us the equation of the circle:

Just as we can find the equation of a circle if we are given its radius and center, so too can we determine the center and radius if we are just given the equation. Let us see how this is done below.

### Example 2: Finding the Center and Radius of a Circle from Its Equation in Standard Form

Find the center and radius of the circle .

### Answer

Let us remember that for a circle with center and radius , the standard form of its equation is

We have been given the equation of a circle that is almost in this form, although the constant term is on the wrong side of the equation. Adding 100 to both sides gets it into this form, giving us

Comparing this to the general form of the equation, we can see that

This means that the center is , and the radius .

Although the equation of a circle we have seen so far is the standard form that is used, a more general form of the equation exists. Let us recall that the standard form is

If we expand the parentheses, this gives us

Rearranging this a bit so the terms with higher powers of and are on the left, we get

Notice that , and are all constants, so they can be written as , , and respectively. This results in the following equation.

### Definition: Equation of a Circle (General Form)

The general form of the equation of a circle is where , , and are constants.

We note that this form does not directly involve the center and radius in the expression; instead, if we are given the center and the radius of a circle and want the general form, we must first write the equation in its standard form and then expand the parentheses. Let us see an example of this.

### Example 3: Writing the General Form of a Circleβs Equation given Its Center and Diameter

Give the general form of the equation of the circle of center and diameter 10.

### Answer

Recall that the general form of the equation of a circle is where , , and are constants that need to be determined. To write the equation of a circle in this form, we can begin by writing it in its standard form and expanding the parentheses. The standard form is where is the center of the circle and is the radius.

In this instance, the circle has center and diameter 10. Since the diameter is twice the radius, the radius is 5. Thus, , , and . Substituting these in, we get the following standard form of the equation:

We now want to get the equation into the general form, which we can achieve by expanding the parentheses. This gives us

Finally, we can rearrange this to get the required form:

Just as we demonstrated that the standard form of the equation of a circle can give us the center and radius, we can imagine that
it is also possible to find the center and radius of a circle given the general form. This is indeed the case; however, as this
involves *undoing* the binomial expansion, we therefore need to be able to factor the equation by completing the square. Let
us detail this procedure.

### How To: Finding the Center Coordinates and the Radius given the Equation of a Circle in Its General Form

Suppose that we are given the equation of a circle in the general form and want to find the center and radius of the circle. We can do this by completing the square.

- First, we rearrange the equation as follows
- Recall that we can complete the square by using a substitution of the form . Completing the square for both parentheses in the equation gives us
- Next, we can rearrange this so the constant terms are all on the right-hand side to get
- As this is the standard form of the equation of a circle, this tells us that the center is at and the radius is .

Let us apply this procedure to find the center and radius for a given equation of a circle in general form.

### Example 4: Finding the Center and Radius of a Circle given Its Equation in General Form

By completing the square, find the center and radius of the circle .

### Answer

As specified in the question, we are asked to find the center and radius of a circle given its equation in general form by completing the square. To do this, we can use the following substitutions:

Putting these into the given equation, we get

Taking the constants to the other side, this is

This is the standard form for the equation of a circle. In other words, we have where is the center and is the radius of the circle. Therefore, the center is , and the radius is .

Up until now, we have either been given the center and radius of a circle and have to write the equation or vice versa. Sometimes, however, we are not explicitly given all the information we need and instead have to work it out first through deduction. Let us consider an example of this.

### Example 5: Writing the Equation of a Circle in Standard Form given Its Center and a Point on the Circumference

A circle has center and goes through the point . Find the equation of the circle.

### Answer

Recall that the equation of a circle in its standard form is where is the circleβs center and is the radius.

In this example, we have been given the center but not the radius. If we substitute just and into the above formula and leave as an unknown, we get

Even though we do not have the radius, we know that any point on the circle has to satisfy this equation. Thus, if we put the point into the above equation, we should get the correct value for . Doing this gives us

Therefore, , and the complete equation is

An alternative way to complete the above example is to find the radius by calculating the distance between the center and the given point. That is to say, if is a point on the circle, this means that its distance from the center point is equal to the radius. Recall that the distance between two points, and , is given by the formula

If we put the points and into this equation, we get

This tells us the radius is ; hence, . This is equivalent to the above method because the standard equation of a circle is in essence just an equation for the distance between the center and a variable point. So, regardless of whether we calculate the distance directly or substitute a point into the equation, we are doing the same calculation.

For our final example, we will demonstrate what happens when we are given neither the radius nor the center of the circle but can deduce this information to help us find the equation.

### Example 6: Finding the Equation of a Circle given Two Points on the Circumference and a Line Passing through the Center

Determine the general form of the equation of the circle that passes through the two points and , given that the circleβs center lies on the straight line .

### Answer

Recall that the general form of the equation of the circle is given by where , , and are constants that need to be determined. To get to this form, we need to find the center of the circle and its radius, but we have not been given either.

Let us analyze the information we have been given and see how we can use it to solve the problem. We may not have the center of the circle, but we have two points that lie on the circle, and we know that all points on the circle are equidistant from the center. Let us suppose the center is . Since the distances from the center to each of the points and are equal, this means we have the following equation: where the left-hand side is the (squared) distance from to and the right-hand side is the (squared) distance from to . By expanding the parentheses, we get

From here, we notice that the and terms cancel out. Thus, rearranging everything to the left-hand side, we get and dividing by 2, we get

Note that this equation tells us that point C lies on the line of equation . That is to be expected since the set of points that are equidistant to two distinct points forms a line that bisects the two points. We show this line below.

Now, we know that the center of the circle must lie on this line. By itself, this would not be enough to solve the problem, but recall that we have also been given that the center lies on a different line, . Assuming the lines are not parallel, they should intersect at exactly one point, which is where the center must be. We show this below.

We can find the intersection by substitution (i.e., we rearrange the second line () to be in terms of ): and substitute this value for into the line to get

Thus, the -coordinate of the center is . We can find the -coordinate by substitution too. Putting the value for into , we get

Thus, the center is at . Next, we need to find the radius. We can find this by taking the distance from to either point (let us just choose ). This is

With this, we can now form the standard equation for a circle, which we can recall is where is the center and is the radius. Substituting in , , and , this is

The final part of this question is to write the equation in its general form. We can do this by expanding the parentheses and rearranging, giving us

Although not required, plotting this equation gives us the following diagram.

Let us finish by considering the key points we have learned in this explainer.

### Key Points

- A circle with center and radius has the following equation (in standard form):
- The general form of the equation of a circle is where , , and are constants.
- The general form can be obtained by expanding the parentheses in the standard form.
- To find the center and radius from an equation in general form, we can complete the square to factor the equation into standard form.
- In problems where we are not given the center or radius, we can find these values by deduction and using the properties of a circle.