Lesson Explainer: Multiplying and Dividing Square Roots | Nagwa Lesson Explainer: Multiplying and Dividing Square Roots | Nagwa

Lesson Explainer: Multiplying and Dividing Square Roots Mathematics

In this explainer, we will learn how to multiply and divide square roots and use that to simplify expressions.‌

We can begin by recalling that 𝑎 is the nonnegative number such that 𝑎=𝑎. In particular, this tells us that if 𝑎0, then 𝑎=𝑎×𝑎=𝑎.

This gives us the following result.

Property: Product of the Square Root of a Nonnegative Real Number

If 𝑎 is a nonnegative real number, then 𝑎×𝑎=𝑎.

We can use this property, alongside the commutative and associative properties of multiplication, to simplify expressions involving calculating the product of the square root of a real number with itself. For example, 23×63=(2×6)×3×3=12×3=36.

Let’s now see another example where we need to use this property to simplify an expression.

Example 1: Multiplying Two Radical Numbers with the Same Base

Calculate 123×73.

Answer

We can rewrite this expression by using the commutative and associative properties of the multiplication of real numbers as follows: 123×73=(12×7)×3×3.

We can then recall that, for any nonnegative real number 𝑎, 𝑎×𝑎=𝑎. Hence, (12×7)×3×3=84×3=252.

Let’s see another example of using this property to simplify an expression.

Example 2: Multiplying a Radical Number and a Radical Expression with the Same Base

Simplify 571+7.

Answer

We start by distributing the product over the parentheses to get 571+7=57×1+57×7.

We can simplify this expression by recalling that 1 is the multiplicative identity, so multiplying by 1 leaves the value unchanged, and we can use the associativity of multiplication to rewrite the second term as 57×1+57×7=57+5×7×7.

We can then simplify this expression by recalling that, for any nonnegative real number 𝑎, 𝑎×𝑎=𝑎. Hence, 57+5×7×7=57+(5×7)=57+35.

In our next example, we will simplify the product of two radical expressions.

Example 3: Multiplying two Radical Expressions and Simplifying

Express 510+3351033 in its simplest form.

Answer

We start by distributing over the parentheses to get 510+3351033=510×510+510×33+33×510+33×33.

Taking out the factors of 1 and canceling like terms gives 510×510+510×33+33×510+33×33=510×510510×33+33×51033×33.

We can reorder the second term and simplify to get 510×51033×510+33×51033×33=510×51033×33.

We then rearrange the expressions and evaluate to get 510×51033×33=(5×5)×10×10(3×3)×3×3=2510×1093×3.

We can then simplify this expression by recalling that, for any nonnegative real number 𝑎, 𝑎×𝑎=𝑎. Hence, 2510×1093×3=(25×10)(9×3)=25027=223.

We have demonstrated how to manipulate and evaluate expressions involving products of square roots. We can then ask, “What happens when we multiply the square roots of any two real numbers?” Of course, we cannot take the square root of negative numbers, so we will begin by assuming that our numbers are nonnegative real numbers, 𝑎 and 𝑏. We can then note that we know how to simplify 𝑎×𝑎 and 𝑏×𝑏, which we can use to see the following: 𝑎×𝑏=𝑎×𝑏×𝑎×𝑏=𝑎×𝑎×𝑏×𝑏=𝑎×𝑏.

We can then take the square root of both sides of the equation. Then, by using the fact that 𝑎 and 𝑏 are nonnegative, we have that 𝑎×𝑏=𝑎×𝑏.

We have therefore shown the following property.

Property: Product of Square Roots of Nonnegative Real Numbers

If 𝑎 and 𝑏 are nonnegative real numbers, then 𝑎×𝑏=𝑎×𝑏.

We can use this result to simplify expressions involving the product of the square roots of nonnegative real numbers. For example, 6×24=6×24=144=12.

We can follow a similar process to evaluate the quotient of two square roots. This time we assume that 𝑎 and 𝑏 are nonnegative and that 𝑏 is nonzero. We can then apply the same reasoning as before to see the following: 𝑎𝑏=𝑎𝑏×𝑎𝑏=𝑎×𝑎𝑏×𝑏=𝑎𝑏.

Taking square roots of both sides of the equation gives us the following result.

Property: Square Root of the Quotient of Nonnegative Real Numbers

If 𝑎 and 𝑏 are nonnegative real numbers and 𝑏0, then 𝑎𝑏=𝑎𝑏.

We can use this process to simplify expressions involving the quotient of the square roots of nonnegative real numbers. For example, 182=182=9=3.

It is worth noting that both of these results also work in the other direction. For example, 254=254=52.

Let’s now see an example of how to use these properties to write an expression involving radicals in its simplest form.

Example 4: Squaring a Radical Expression and Simplifying

Express 7+384 in its simplest form.

Answer

We first distribute the exponent over the parentheses to get 7+384=7+37+384=7×7+7×3+3×7+3×384.

We can reorder the third term and simplify as follows: 7×7+7×3+7×3+3×384=7×7+27×3+3×384.

We then recall that if 𝑎 is a nonnegative real number, then 𝑎×𝑎=𝑎. This means that we can simplify this expression as follows: 7×7+27×3+3×384=7+27×3+384=10+27×384.

We can simplify further by recalling that if 𝑎 and 𝑏 are nonnegative real numbers, then 𝑎×𝑏=𝑎×𝑏. We can apply this in two different ways to this expression.

First, 7×3=7×3=21.

Second, we can factor the radicand 84 into primes to get 84=2×2×3×7=4×21. We can use this to simplify the radical: 84=4×21=4×21=221.

Hence, 10+27×384=10+221221=10.

In our next example, we will simplify an expression involving the quotient of two radicals with different bases.

Example 5: Dividing Two Radical Numbers with Different Bases

Express 102 in its simplest form.

Answer

We first recall that if 𝑎 and 𝑏 are nonnegative real numbers and 𝑏0, then 𝑎𝑏=𝑎𝑏. Applying this to the given expression yields 102=102.

We note that 10 and 2 share a common factor of 2. Canceling this shared factor yields 102=5×21×2=5.

In our next example, we will simplify an expression using all of the properties we have found in this explainer.

Example 6: Simplifying an Expression Involving the Multiplication and Division of Radicals

Express 28×20+36 in its simplest form.

Answer

We start by distributing over the parentheses to get 28×20+36=28×20+28×36=2×208+2×368.

We then recall that if 𝑎 is a nonnegative real number, then 𝑎=𝑎, and if 𝑎 and 𝑏 are nonnegative real numbers, then 𝑎×𝑏=𝑎×𝑏. Applying this to the expression gives 2×208+2×368=2×208+2×68=2×108+628=2108+628.

We then recall that if 𝑎 and 𝑏 are nonnegative real numbers and 𝑏0, then 𝑎𝑏=𝑎𝑏. Applying this we get 2108+628=2108+628=254+614.

We then note that 54=54=52 and 14=14=12, so 254+614=252+62=5+3=3+5.

Let’s finish by recapping some of the important points from this explainer.

Key Points

  • If 𝑎 is a nonnegative real number, then 𝑎×𝑎=𝑎.
  • If 𝑎 and 𝑏 are nonnegative real numbers, then 𝑎×𝑏=𝑎×𝑏.
  • If 𝑎 and 𝑏 are nonnegative real numbers and 𝑏0, then 𝑎𝑏=𝑎𝑏.

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