The portal has been deactivated. Please contact your portal admin.

Lesson Explainer: Multistep Equations Mathematics • 7th Grade

In this explainer, we will learn how to solve multistep equations over the rational numbers.

Let’s start by recalling what we mean by β€œan equation” in mathematics. An equation is formed when two expressions of equal value are connected by an equals sign. For example, 4π‘₯+7=27.

Here, we know that the value of the expression 4π‘₯+7 is equal to 27. Equations are a powerful tool in mathematics; we often represent real-world situations using equations and then solve these to find unknown values.

We can think of an equation as a balance between two things. Much like with a set of balance scales, to keep the scales in balance, we have to add or remove equal masses from both sides of the scales. The same is true for an equation. If we apply an operation to one side of the equation, we must also apply the same operation to the other side to ensure that the values of the two sides remain equal.

Consider the equation that we mentioned earlier, 4π‘₯+7=27.

We could, for example, add 3 to each side of the equation to get 4π‘₯+7+3=27+3, which simplifies to 4π‘₯+10=30.

This represents an equivalent equation, as we have performed the same operation (in this case, addition) to each side, but this has not gotten us any closer to solving the equation. To solve an equation, we need to perform operations to both sides of the equation until we can write it in the form π‘₯=…. So, for the equation 4π‘₯+7=27, a sensible first step would be to subtract 7 from each side to get 4π‘₯+7βˆ’7=27βˆ’7, which simplifies to 4π‘₯=20.

Now, we know that 4 times something is equal to 20, so to find that something, we divide both sides by 4. We find that π‘₯=5.

An interesting note here is that although we could have divided the equation through by 4 first, this would have complicated our working out, as we would have had to divide all terms on each side by 4, which would have resulted in the equation π‘₯+74=274.

This is still equivalent, but it has introduced fractions, which are more difficult to work with. Therefore, when solving equations, we also consider the order of the operations that we apply to each side. This is particularly important when working with multistep equations.

What do we mean by β€œmultistep equation”? Linear equations are often classified by the number of β€œsteps” that are required to solve them. For example, an equation such as π‘₯+8=12 would often be referred to as a β€œone-step” equation, as we could find the solution by subtracting 8 from both sides. Similarly, an equation such as the one that we have just solved, 4π‘₯+7=27, is often referred to as a two-step equation, as two steps are required to solve it, namely subtracting 7 and dividing through by 4.

Multistep equations are a little more broadly defined, but intuitively, they are equations that require multiple steps to solve. This includes equations that contain an unknown variable more than once, including on each side of the equals sign. Examples of multistep equations include 4(2π‘₯βˆ’3)βˆ’2(π‘₯+5)=βˆ’10 and 4π‘₯βˆ’7=2π‘₯+9.

In both cases, the additional steps involve simplifying the equations down to two-step equations.

Our strategy when solving multistep equations should always be to apply operations to each side of the equation that simplify the equation into a form that is easier to work with.

A final noteworthy point when solving equations is that when we have solved an equation, we can always check our answer by substituting our solution back into the original equation. Recall again our original two-step equation, 4π‘₯+7=27. we found that the solution to this was π‘₯=5. If we substitute this back into our equation, we get 4(5)+7=27, which simplifies to 20+7=2727=27.

As the left-hand side is equal to the right-hand side, we know that our solution is correct.

Let’s now see some examples of solving equations by isolating the variable on one side of the equation.

Example 1: Solving a Linear Equation to Find a Rational Solution

Find the value of π‘₯ if π‘₯+12=15.

Answer

We begin by recalling that we want to isolate π‘₯ on one side of the equation. We can do this by subtracting 12 from both sides of the equation since this will remove the addition of 12 from the left-hand side. We have π‘₯+12βˆ’12=15βˆ’12π‘₯=15βˆ’12.

We then recall that to subtract two fractions, we need their denominators to be equal. We can note that 2 and 5 share no common factors, so their lowest common multiple is their product: 2Γ—5=10. Thus, we will rewrite both fractions to have a denominator of 10. We get π‘₯=1Γ—25Γ—2βˆ’1Γ—52Γ—5=210βˆ’510.

Now that the denominators are equal, we can subtract the numerators to find the value of π‘₯. This gives us π‘₯=2βˆ’510=βˆ’310.

In our next example, we will look at how to solve an equation with an unknown and a constant on each side, a multistep equation.

Example 2: Solving a Multistep Linear Equation to Find a Rational Solution

Find the value of π‘₯ if 8π‘₯+2=6βˆ’2π‘₯.

Answer

To solve this equation, we need to isolate the variable π‘₯ on either the left- or right-hand side by applying the same operations to each side of the equation.

We can do this by either adding 2π‘₯ to each side of the equation or subtracting 8π‘₯ from each side. Generally, it will simplify our working if we identify the π‘₯-term with the smallest coefficient, so we will add 2π‘₯ to each side. This gives us 8π‘₯+2+2π‘₯=6βˆ’2π‘₯+2π‘₯.

We recall that we can add the π‘₯-terms by collecting like terms and simplifying. This yields (8+2)π‘₯+2=6+(βˆ’2+2)π‘₯10π‘₯+2=6.

Now we subtract 2 from both sides of the equation to get 10π‘₯+2βˆ’2=6βˆ’210π‘₯=4 and divide both sides of the equation by 10 to get 10π‘₯10=410π‘₯=410.

Finally, we see that 4 and 10 share a factor of 2. Therefore, we can simplify as follows: π‘₯=2Γ—22Γ—5=25.

It is worth noting that we can check this answer by substituting π‘₯=25 into both sides of the original equation and checking they are equal. This is generally good practice, but it is not an essential step in our calculation, provided we have been accurate in our original calculation.

Substituting π‘₯=25 into the left-hand side of the equation yields 8π‘₯+2=8ο€Ό25+2=8Γ—25+2=165+105=265.

Substituting π‘₯=25 into the right-hand side of the equation yields 6βˆ’2π‘₯=6βˆ’2ο€Ό25=6βˆ’2Γ—25=305βˆ’45=265.

Since both sides of the equation are equal when π‘₯=25, we have confirmed that this is a solution to the equation.

In our next example, we will look at how to solve an equation that contains expressions between parentheses.

Example 3: Solving a Multistep Linear Equation to Find a Rational Solution

Find the value of π‘₯ if 2(1βˆ’3π‘₯)βˆ’(3+6π‘₯)=5βˆ’7π‘₯.

Answer

To solve an equation, we need to isolate the variable on one side of the equation by applying the same operations to both sides of the equation.

Before applying any operations to the equation, we can start by simplifying the left-hand side: we distribute 2 over the first set of parentheses and negative 1 over the second set of parentheses. Remember that to distribute over the parentheses, we multiply each term in the parentheses by the multiplier. We get (2Γ—1)+(2Γ—βˆ’3π‘₯)+(βˆ’1Γ—3)+(βˆ’1Γ—6π‘₯)=5βˆ’7π‘₯2βˆ’6π‘₯βˆ’3βˆ’6π‘₯=5βˆ’7π‘₯.

We can simplify the left-hand side of the equation by combining like terms: 2βˆ’3βˆ’6π‘₯βˆ’6π‘₯=5βˆ’7π‘₯βˆ’1βˆ’12π‘₯=5βˆ’7π‘₯.

We can now rearrange the equation such that all of the π‘₯-terms are on the same side of the equation. We add 12π‘₯ to both sides of the equation to get βˆ’1βˆ’12π‘₯+12π‘₯=5βˆ’7π‘₯+12π‘₯βˆ’1=5+5π‘₯.

Now, we subtract 5 from each side of the equation: βˆ’1βˆ’5=5+5π‘₯βˆ’5βˆ’6=5π‘₯.

Finally, we divide the equation through by 5 to get βˆ’65=π‘₯.

As we mentioned in the introduction, equations are often used as a useful tool in mathematics to solve real-world problems.

For example, if we are told that a rectangular field has a perimeter of 42 m and that its length is 3 m longer than its width 𝑀, then we can note that the length of the field is 𝑀+3.

The perimeter of a rectangle is the sum of twice its side lengths: 2𝑀+2(𝑀+3)=42.

We can distribute 2 over the parentheses on the left-hand side of the equation to get 2𝑀+2𝑀+6=42.

Simplifying then gives 4𝑀+6=42.

Subtracting 6 from both sides yields 4𝑀=42βˆ’6=36.

Dividing both sides of the equation by 4 then gives us 𝑀=364=9.m

We can check this answer in two ways. We can sketch a rectangle with a width of 9 m and a length of 9+3=12m and check its perimeter is 42 m.

We have 12+9+12+9=42.m

Alternatively, we can substitute 𝑀=9 into our original equation to check that both sides of the equation are equal. We have 2𝑀+2(𝑀+3)=2(9)+2(9+3)=18+2(12)=18+24=42.m

Sometimes in mathematics, we might be faced with a real-world scenario that we can represent using a linear equation and subsequently solve. We will demonstrate this in our next example.

Example 4: Forming and Solving a Linear Equation for a Real-World Problem

The sum of the weights of three people is 154 kg. If the first person is 2 kg heavier than the second person and the second person is 1 kg lighter than the third person, find each of their weights.

Answer

To answer this question, we need to form and solve an equation using the given information. We can label the weight of each person in kilograms using a different variable, say π‘€οŠ§, π‘€οŠ¨, and π‘€οŠ©.

Let’s now write each piece of information as an equation. First, the sum of the weights of the three people is 154 kg, so 𝑀+𝑀+𝑀=154.

Let’s consider that the first person is 2 kg heavier than the second person. This means that if we add 2 to the second person’s weight, we must get the weight of the first person. So, 𝑀=𝑀+2.

Similarly, we are told that the second person is 1 kg lighter than the third person, so π‘€βˆ’1. must be the same as π‘€οŠ¨: 𝑀=π‘€βˆ’1.

We can rearrange this equation so that π‘€οŠ© is written in terms of π‘€οŠ¨. We add 1 to both sides of the equation to get 𝑀=𝑀+1.

We now have expressions for the weights of the first person and the third person in terms of π‘€οŠ¨. We can substitute these expressions into the equation for the sum of the weights to get 𝑀+𝑀+𝑀=154(𝑀+2)+𝑀+(𝑀+1)=154.

Collecting like terms on the left-hand side of the equation yields 3𝑀+3=154.

Subtracting 3 from both sides of the equation gives 3𝑀=154βˆ’3=151.

Dividing both sides of the equation by 3 then gives 𝑀=1513.kg

We can substitute this value of π‘€οŠ¨ into our equations for π‘€οŠ§ and π‘€οŠ© to find the weights of the other two people. We have 𝑀=𝑀+2=1513+2=1573,𝑀=𝑀+1=1513+1=1543.kgkg

Hence, the weight of the first person is 1573 kg, that of the second is 1513 kg, and that of the third is 1543 kg.

In our final example, we will look at a problem involving the interior angles of a triangle. Much like with the previous example, we will ultimately solve the problem by forming and then solving an equation, but to do this, we will need to apply our knowledge about the sum of the interior angles of a triangle.

Example 5: Forming and Solving a Linear Equation for a Real-World Problem

In the following figure, find the measure of all the angles in triangle 𝐴𝐡𝐢.

Answer

We begin by recalling that the sum of the measures of the interior angles in a triangle is equal to 180∘. Since we are told the measure of each angle, we can form an equation by finding their sum. We have 180=(π‘₯+1)+(3π‘₯βˆ’1)+(3π‘₯).∘∘∘∘

We can simply write this equation without the degree symbol for simplicity: 180=(π‘₯+1)+(3π‘₯βˆ’1)+3π‘₯.

We can combine like terms by adding their coefficients. This gives 180=π‘₯+3π‘₯+3π‘₯+1βˆ’1180=7π‘₯.

We can then divide both sides of the equation through by 7 to solve for π‘₯: π‘₯=1807.

We can then substitute this value for π‘₯ into each of the expressions for the measures of the angles.

For angle ∠𝐴, we get π‘šβˆ π΄=1807+1=1807+77=1877.∘

For angle ∠𝐡, we get π‘šβˆ π΅=3ο€Ό1807οˆβˆ’1=5407βˆ’77=5337.∘

For angle ∠𝐢, we get π‘šβˆ πΆ=3ο€Ό1807=5407.∘

Hence, π‘šβˆ π΄=1877,π‘šβˆ π΅=5337,π‘šβˆ πΆ=5407.∘∘∘and

Let’s finish by recapping some of the important points from this explainer.

Key Points

  • We can solve equations by applying the same operations to both sides of the equation with the aim of isolating the variable on one side of the equation.
  • A multistep equation is an equation in which multiple steps are needed to isolate the variable.
  • It is important to check the order of operations when forming equations from a real-world scenario and also when solving them.

Nagwa uses cookies to ensure you get the best experience on our website. Learn more about our Privacy Policy.