Lesson Explainer: Distance on the Coordinate Plane: Horizontal and Vertical | Nagwa Lesson Explainer: Distance on the Coordinate Plane: Horizontal and Vertical | Nagwa

Lesson Explainer: Distance on the Coordinate Plane: Horizontal and Vertical Mathematics • 6th Grade

In this explainer, we will learn how to find the horizontal or vertical distance between two points on the coordinate plane.

Let’s look at a couple of examples to understand how it works.

Distance between Two Points in a Coordinate Plane

The distance between any two points 𝐴(𝑥,𝑦) and 𝐵(𝑥,𝑦) can be found by applying the Pythagorean theorem. It gives 𝐴𝐵=(𝑥𝑥)+(𝑦𝑦).

Example 1: Finding the Distance from a Point to the Origin

Let us consider 𝐴(3,4), 𝐵(3,0), and 𝐶(0,4) in a coordinate system of origin 𝑂(0,0). Using the Pythagorean theorem, find the distance between 𝑂 and 𝐴.

Answer

We know from the given coordinates that 𝐴 and 𝐵 lie on a vertical line, as well as 𝑂 and 𝐶, as the two points in each pair have the same 𝑥-coordinate. Similarly, 𝐴 and 𝐶 lie on a horizontal line, as well as 𝑂 and 𝐵. 𝐴𝐵𝑂𝐶 is thus a rectangle, and 𝐴𝐵𝑂 and 𝐴𝐶𝑂 are congruent right triangles, with their right angles, respectively, at 𝐵 and 𝐶.

The distance between 𝑂 and 𝐴 is the length of 𝑂𝐴, and it can be found by applying the Pythagorean theorem either in 𝐴𝐵𝑂 or in 𝐴𝐶𝑂. In 𝐴𝐵𝑂, for instance, 𝑂𝐴 is the hypotenuse, while 𝑂𝐵 and 𝐵𝐴 are the legs. This gives 𝑂𝐵+𝐴𝐵=𝑂𝐴3+4=𝑂𝐴.

We find that 𝑂𝐴=5.

Example 2: Finding the Distance between Two Points Using the Pythagorean Theorem

Let us now consider 𝐴(7,9) and 𝐵(10,5) in a coordinate system of origin 𝑂(0,0). 𝐴𝐵𝐶 has a right angle at 𝐶 and is such that 𝐵𝐶 is parallel to the 𝑥-axis and 𝐴𝐶 is parallel to the 𝑦-axis. Using the Pythagorean theorem, find the distance between 𝐴 and 𝐵.

Answer

We see that the coordinates of 𝐶 are completely defined by those of 𝐴 and 𝐵: they are (𝑥,𝑦), here (7,5).

In 𝐴𝐵𝐶, the hypotenuse is 𝐴𝐵 and the legs are 𝐴𝐶 and 𝐶𝐵. Since 𝐶 and 𝐵 lie on a horizontal line, the length of 𝐶𝐵 is simply given by 𝐶𝐵=|𝑥𝑥|. And we know that 𝑥=𝑥, so we have 𝐶𝐵=|𝑥𝑥|=107=3.

Similarly, the length of 𝐴𝐶 is 𝐴𝐶=|𝑦𝑦|, and as 𝑦=𝑦, we find 𝐴𝐶=|𝑦𝑦|=|95|=4.

Applying the Pythagorean theorem in 𝐴𝐵𝐶 gives 𝐴𝐵=𝐶𝐵+𝐴𝐶𝐴𝐵=(𝑥𝑥)+(𝑦𝑦).

𝐴𝐵 is a length, so we can write 𝐴𝐵=(𝑥𝑥)+(𝑦𝑦)𝐴𝐵=3+4=5.

The equation we have established to find the distance between points 𝐴 and 𝐵 is true for any couple of points.

Example 3: Finding Distances on a Coordinate Plane

Find the distance between the points 𝐴 and 𝐵.

Answer

  1. We find the coordinates of points 𝐴 and 𝐵 from the diagram: 𝐴(3,4) and 𝐵(0,3).
  2. We know that the distance between 𝐴 and 𝐵 is the length of 𝐴𝐵 and is 𝐴𝐵=(𝑥𝑥)+(𝑦𝑦).
  3. We plug the coordinates of 𝐴 and 𝐵 into the above equation: 𝐴𝐵=(0(3))+(34)𝐴𝐵=3+(7)𝐴𝐵=9+49𝐴𝐵=58.lengthunits

Note that if you do not remember the formula, it is very easy to retrieve it by applying the Pythagorean theorem in 𝐴𝐵𝐶 with 𝐶(𝑥,𝑦) or 𝐶(𝑥,𝑦).

Example 4: Finding Distances on a Coordinate Plane

Quadrilateral 𝑃𝑄𝑅𝑆 has vertices 𝑃(1,6), 𝑄(5,6), 𝑅(5,3), and 𝑆(1,3). Find the length of 𝑄𝑆.

Answer

  1. We find the coordinates of points 𝑄 and 𝑆 from the diagram: 𝑄(5,6) and 𝑆(1,3).
  2. We know that the length of 𝑄𝑆 is 𝑄𝑆=𝑥𝑥+𝑦𝑦.
  3. We plug the coordinates of 𝑄 and 𝑆 into the above equation: 𝑄𝑆=(15)+(36)𝑄𝑆=(6)+(3)𝑄𝑆=36+9𝑄𝑆=45,
    and as 45=95,𝑄𝑆=95,
    and because 𝑎𝑏=𝑎𝑏,𝑄𝑆=95𝑄𝑆=35.

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