Lesson Explainer: Powers and Exponents for Rational Numbers | Nagwa Lesson Explainer: Powers and Exponents for Rational Numbers | Nagwa

Lesson Explainer: Powers and Exponents for Rational Numbers Mathematics • First Year of Preparatory School

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In this explainer, we will learn how to identify the base and exponent in power formulas, write them in exponential and expanded forms, and evaluate simple powers.

We begin by recalling that we can represent repeated multiplication as a power. For example, 2 is defined as the product of five twos as follows. 2=2×2×2×2×2.times

We call 2 the base and 5 the exponent. We can extend this definition to general rational bases. In this case, if 𝑛 is a positive integer and 𝑎𝑏 is a rational number, then 𝑎𝑏 will be the product of 𝑛 lots of 𝑎𝑏.

For example, we can evaluate 12 by finding the product of three halves as follows: 12=12×12×12=1×1×12×2×2=18.

Similarly, we can evaluate 23 by repeated multiplication as shown: 23=23×23×23×23=(2)×(2)×(2)×(2)3×3×3×3=1681.

We can follow this same process in reverse. Let’s say we want to write 278 in the exponential form. We can factor the numerator and denominator into primes as follows: 278=3×3×32×2×2.

We can then split the multiplication as shown: 3×3×32×2×2=32×32×32.

We see that 278 is the product of three lots of 32, so we can write this in the exponential form 32×32×32=32.

Thus, 278=32.

Let’s now see some examples involving the powers of rational numbers.

Example 1: Understanding Powers

What terminology do we use to describe the 12 in the expression 12 and the 5 in the expression 12?

Answer

We recall that an expression of the form 𝑎 is called an exponential expression or the 𝑛th power of 𝑎. We call 𝑎 the base of the expression and 𝑛 the exponent or power.

In the expression 12, we note that 12 is the number that is being taken to a power and 5 is the power itself. Hence, 12 is called the base of the expression and 5 is the exponent of the expression.

In our next example, we will simplify an expression by rewriting it in the exponential form.

Example 2: Writing a Numerical Expression as an Exponent

What is 411×411×411×411×411×411×411?

  1. 411
  2. 411
  3. 411
  4. 711
  5. 2811

Answer

We could evaluate this expression by multiplying all of the numerators and denominators. This would give us 411×411×411×411×411×411×411=4×4×4×4×4×4×411×11×11×11×11×11×11.

However, the options are given as powers. So, instead of evaluating these expressions, we can simplify by recalling that repeated multiplication can be rewritten as exponentiation.

In particular, the product of 7 lots of 411 can be written by raising 411 to an exponent of 7.

We have seen that positive integer powers can be thought of as repeated multiplication of the base. In general, if 𝑎𝑏 and 𝑛 is a positive integer, we have 𝑎𝑏=𝑎𝑏×𝑎𝑏××𝑎𝑏.times

We can evaluate the right-hand side of the equation by multiplying the numerators and denominators separately as follows: 𝑎𝑏=𝑎𝑏×𝑎𝑏××𝑎𝑏=𝑎×𝑎××𝑎𝑏×𝑏××𝑏=𝑎𝑏.times

In other words, we can raise a rational number to a positive integer exponent by raising its numerator and denominator to the exponent separately.

For example, we saw that 12=12×12×12=18. We could have instead evaluated this by cubing the numerator and denominator: 12=12=18.

We can write this result formally as follows.

Property: Powers of Rational Numbers

Since a positive integer power of a rational base is defined by repeated multiplication, we can show that if 𝑛 is a positive integer and 𝑎𝑏, then 𝑎𝑏=𝑎𝑏×𝑎𝑏××𝑎𝑏=𝑎𝑏.times

In other words, we can raise the numerator and denominator to the power separately.

In our next example, we will evaluate a power where the base is rational.

Example 3: Evaluating Rational Numbers Raised to a Power

Find the value of 65, giving your answer in its simplest form.

Answer

We can evaluate this expression in two ways. We begin by recalling that exponentiation is defined by repeated multiplication. So, 65 is the product of 3 lots of 65 as shown: 65=65×65×65.

We can multiply the numerators and denominators separately to get 65×65×65=(6)×(6)×(6)5×5×5=216125.

We can also evaluate this expression by recalling the general result for powers of rational numbers. In general, if 𝑛 is a positive integer and 𝑎𝑏, then 𝑎𝑏=𝑎𝑏.

Hence, 65=65=(6)5=216125.

In our next example, we will evaluate an exponential expression involving multiple exponential factors.

Example 4: Calculating a Numerical Expression Using Powers

Evaluate the expression 23×65÷45, giving your answer as a fraction in simplest form.

Answer

To evaluate this expression, we first need recall that the order of operations tells us to start with the powers. We then recall that if 𝑛 is a positive integer and 𝑎𝑏, then 𝑎𝑏=𝑎𝑏.

Hence, we can evaluate each power as follows: 23=23=827,65=65=3625,45=45=256625.

We can substitute these values into the expression to get 23×65÷45=827×3625÷256625.

Next, we need to evaluate the innermost parentheses. We do this by multiplying the numerators and denominators separately. We have 827×3625=8×3627×25.

We can note that both 36 and 27 are divisible by 9 to help simplify. 8×3627×25=8×9×49×3×25=8×43×25=3275.

Substituting this value into the expression gives 827×3625÷256625=3275÷256625.

We can now recall that dividing by a fraction is the same as multiplying by its reciprocal. This gives 3275÷256625=3275×625256.

We can then simplify this expression by factoring as follows: 3275×625256=32×62575×256=32×(25×25)(25×3)×(32×8)=253×8=2524.

In our next example, we will find an expression for the volume of a cube from a given expression for its side length.

Example 5: Solving a Word Problem by Taking Powers of Rational Numbers

Find an expression for the volume of the given cube whose side lengths are 2𝑥5.

Answer

We begin by recalling that the volume of a cube is given by the cube of its side length. So, if the cube has side length 𝑎, then its volume is 𝑎×𝑎×𝑎=𝑎. In this case, the side length is 2𝑥5, so its volume is given by the cube of this expression: 2𝑥5.

We can simplify this by writing the product out in full. We find the product of 3 lots of 2𝑥5 to get 2𝑥5=2𝑥5×2𝑥5×2𝑥5=(2𝑥)×(2𝑥)×(2𝑥)5×5×5.

We then recall that to multiply monomials, we multiply the coefficients and add the powers of the shared variables. Thus, (2𝑥)×(2𝑥)×(2𝑥)5×5×5=2×2×2×𝑥125=8𝑥125.()

In our final example, we will evaluate an algebraic expression using the results for the powers of rational numbers.

Example 6: Evaluating an Algebraic Expression Using Powers

If 𝑥=32 and 𝑦=45, find the value of 𝑥𝑦𝑥𝑦, giving your answer as a fraction in simplest form.

Answer

We first substitute the given values into the expression to get 𝑥𝑦𝑥𝑦=32453245.

We now want to evaluate the powers by recalling that if 𝑛 is a positive integer and 𝑎𝑏, then 𝑎𝑏=𝑎𝑏.

So, 32=32=94,45=(4)5=64125.

We can now substitute these values into the expression to get 32453245=94453264125.

We can now evaluate each product by multiplying the numerators and denominators separately. We get 94453264125=9×44×53×(64)2×125.

We can cancel the shared factor of 4 in the first term and 2 in the second term to get 9×44×53×(64)2×125=953×(32)125.

We can then simplify 953×(32)125=95+96125.

Finally, we need to rewrite both fractions to have the same denominator to add them together. We note that 5 is a factor of 125 , so 125 is the lowest common multiple of the denominators. Rewriting the first term to have a denominator of 125 and adding the two fractions together gives us 95+96125=9×255×25+96125=225125+96125=225+96125=129125.

We note that there are no shared factors in the numerator and denominator, so we cannot simply further.

Hence, 𝑥𝑦𝑥𝑦=129125.

Let’s finish by recapping some of the important points from this explainer.

Key Points

  • In an expression of the form 𝑏, we call 𝑏 the base and 𝑛 the power or exponent. We can read this expression as 𝑏 raised to the 𝑛th power.
  • We define positive integer powers by repeated multiplication, known as the expanded form. In general, if 𝑎𝑏 and 𝑛 is a positive integer, then 𝑎𝑏 is a product of 𝑛 lots of 𝑎𝑏. 𝑎𝑏=𝑎𝑏×𝑎𝑏××𝑎𝑏.times
  • In general, we can evaluate the power of a rational number by evaluating the power of the numerator and denominator separately. If 𝑛 is a positive integer and 𝑎𝑏 , then 𝑎𝑏=𝑎𝑏.

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