Lesson Explainer: Properties of Alkanes | Nagwa Lesson Explainer: Properties of Alkanes | Nagwa

Lesson Explainer: Properties of Alkanes Chemistry • Third Year of Secondary School

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In this explainer, we will learn how to write and interpret the names and formulas of alkanes and describe trends in physical properties.

Alkanes are saturated organic compounds that contain covalently bonded carbon and hydrogen atoms. Alkanes are some of the least reactive organic compounds, and they experience some of the weakest intermolecular forces. They do not react with most substances because they do not have electron-rich pi (𝜋) bonds. There are only sigma (𝜎) bonds between atoms, and the electron density is relatively uniform throughout an alkane molecule.

Definition: Alkane

Alkanes are saturated hydrocarbons that contain covalently bonded carbon and hydrogen atoms.

Each carbon atom in an alkane is covalently bonded to four other atoms. This can be seen in the following figure. Some carbon atoms are bonded to two other carbon atoms and two other hydrogen atoms. Other carbon atoms are bonded to just one carbon atom and three hydrogen atoms. All of the carbon and hydrogen atoms are, however, always linked with single covalent bonds. The following image shows three representative alkane molecules. The top line presents the molecules using a ball-and-stick model, and the second and third lines present the molecules using molecular formula and displayed formula representation methods.

HCHHHHCCHHHHHHCHHCHCHHHH

Covalent bonds are made up of negatively charged electrons, and this explains why there is always electrostatic repulsion between all of the four covalent bonds around any one central carbon atom. The covalent bonds are pushed away from each other and end up taking on a shape that minimizes the strength of the repulsive electrostatic forces. The four covalently bonded atoms end up being spread out like the corners of a tetrahedron, and there is an angle of 109.5 between each one of the four covalent bonds.

Methane (CH4) is the simplest alkane. It contains just one carbon atom that is covalently bonded to four hydrogen atoms. Ethane (CH26) is a slightly more structurally complex molecule, and it contains two carbon atoms and six hydrogen atoms. Methane and ethane are the first two members of the straight-chain alkane homologous series and propane (CH38) is the third member.

Example 1: Identifying the Name of the Simplest Alkane

What is the name of the alkane with the chemical formula CH4?

  1. Methane
  2. Methene
  3. Methyne
  4. Ethane
  5. Methanol

Answer

Alkane molecules are relatively simple organic compounds that contain covalently bonded carbon and hydrogen atoms. Some of the alkane molecules are very long and complex and others are very simple and short. Methane (CH4) is the simplest alkane, and it contains just one carbon atom and four covalently bonded hydrogen atoms. We can use this explanation to determine that option A must be the correct answer for this question.

The straight-chain alkane homologous series has the CH()+ general formula, where 𝑛 is the number of carbon atoms and 2𝑛+2 is the number of hydrogen atoms. The formula can be used to determine the molecular formula for any short straight-chain alkane such as ethane or any long straight-chain alkane such as decane. The formula can also be used to determine how many hydrogen atoms there are in an alkane that has some known number of carbon atoms. For example, we can determine that propane has eight hydrogen atoms because the “prop-” term suggests that propane has three carbon atoms and 2𝑛+2=8 when 𝑛=3.

Example 2: Determining the Molecular Formula of an Unknown Alkane Compound

What is the molecular formula of an alkane with 7 carbon atoms?

  1. CH721
  2. CH77
  3. CH716
  4. CH714
  5. CH710

Answer

The straight-chain alkane must be heptane because it has seven carbon atoms. We can determine the number of hydrogen atoms in heptane with the general formula for the straight-chain alkane homologous series. The straight-chain alkane homologous series is described by the general formula CH()+, where 𝑛 is the number of carbon atoms and 2𝑛+2 is the number of hydrogen atoms. We can determine that heptane has sixteen hydrogen atoms because we know that 𝑛=7 and 2𝑛+2=16. The calculations suggest that heptane has the formula CH716. This line of reasoning can be used to determine that option C must be the correct answer for this question.

The general formula CH+ can only be used for straight-chain alkanes such as methane and ethane. This formula only works when there are CH3 groups at the endpoints of an alkane molecule, and this is not true for the series of cyclic alkanes. Cyclic alkanes usually only contain CH2 groups, and this is why we use the formula CH to determine the molecular formula of cyclic alkanes such as cyclopentane and cyclohexane.

Example 3: Identifying the General Formula for the Cyclic Alkane Homologous Series

What is the general formula for the group of compounds to which the following displayed formula is related?

CCHHCHCHHCHHCHHHCHHCHHCCHHHHHH
  1. CH+
  2. CH
  3. CH2
  4. CH
  5. CH

Answer

General formulas are simple mathematical formulas that describe the relative abundance of atoms in separate classes or groups of molecules. The figure depicts a cycloalkane molecule, and cycloalkane molecules generally have two hydrogen atoms for every carbon atom. The CH correctly predicts that there will be twice as many hydrogen atoms (2𝑛) as carbon atoms (𝑛) in a cycloalkane molecule. We can use these statements to determine that option D has to be the correct answer for this question.

The composition of alkanes can become quite complex, and the IUPAC has developed a naming system that helps organic chemists identify and classify different types of alkane molecules. The IUPAC base (root term) is determined from the number of carbon atoms in the longest continuous chain of carbon atoms and the IUPAC prefix is determined from the number and type of any side chains. The suffix will always be the “-ane” term because the IUPAC system uses this suffix to indicate that a molecule is a saturated hydrocarbon.

Number of Carbon AtomsBase (root)SuffixParent Alkane NameParent Alkane FormulaAlkyl Group NameAlkyl Group Formula
1Meth--aneMethaneCH4MethylCH3
2Eth--aneEthaneCH26EthylCH25
3Prop--anePropaneCH38PropylCH37
4But--aneButaneCH410ButylCH49
5Pent--anePentaneCH512PentylCH511
6Hex--aneHexaneCH614HexylCH613
7Hept--aneHeptaneCH716HeptylCH715
8Oct--aneOctaneCH818OctylCH817
9Non--aneNonaneCH920NonylCH919
10Dec--aneDecaneCH1022DecylCH1021

We will use the IUPAC naming system to classify a single organic compound. The displayed formula for the unknown compound is shown below.

HC1C2HHC3HHC4HHC5HHHHC6C7HHHHH

The longest carbon chain contains seven carbon atoms. This suggests that the base or root is the “hept-” term. There are no side chains. This suggests that we should leave the prefix blank. The molecule is a saturated hydrocarbon. This implies that the suffix is “-ane.” We can put these terms together to determine that this molecule should be called heptane.

It is much more challenging to determine the name for a highly branched hydrocarbon because we must describe the longest hydrocarbon chain and all of its substituents. We can consider some representative example systems to understand the IUPAC naming system for a substituted hydrocarbon structure. The following figure shows the displayed formula of one representative hydrocarbon molecule. The unidentified hydrocarbon has the structural formula CHC(CH)CHCH33223.

HC14HC23HC32CH3CH3HHC41HHH

The longest carbon chain contains four carbon atoms, and this implies that the base or root is the “but-” term. There are two methyl group (CH)3 side chains, so the prefix must include the “dimethyl-” term. The methyl groups must be located at the second carbon atom (2) if we are counting carbon atoms from left to right and at the third carbon atom (3) if we are counting carbon atoms from right to left. We will count from left to right because this gives us smaller numbers and we always want the set of smallest possible numbers. If we follow this logic to its endpoint, we should be able to see that this molecule is called 2,2-dimethylbutane.

There are also conventions for classifying alkane derivatives with a halogen or nitro group. The “bromo-” prefix is for a Br substituent, and the “chloro-” prefix is for a Cl substituent. The “nitro-” prefix describes a substituent with the chemical formula NO2. We can see that the following structure on the left side has the name 2-bromopropane, and the one on the right side has the name 2,2-dichlorobutane. The “2-Bromo-” and “2,2-Dichloro-” prefix terms describe the halogen groups on carbon atoms with position number two. The “2-bromo-” prefix is for a single Br group, and the “2,2-dichloro-” prefix is for two Cl groups.

Let us consider one multisubstituted alkane that has both alkyl and chloro- group substituents. The example will explain conventions for classifying alkane derivatives with different types of side chains. The following figure describes the structure of a disubstituted hydrocarbon with one Br side chain and one CH3 group side chain. The molecule name ends with the “-pentane” term because the longest chain has five carbon atoms. The prefix includes the “2-bromo-” and “3-methyl-” terms because there are Br and CH3 group side chains at the carbon atoms with position numbers two and three. The “2-bromo-” term is before the “3-methyl-” term in the molecule name because the letter b is before the letter m in the alphabet. The IUPAC naming system alphabetizes prefix terms based on their first letter. We can use the information in this paragraph to determine that the molecule has the name 2-bromo-3-methylpentane.

The IUPAC naming system is certainly not simple and not always easy to understand and apply. Let us consider more representative molecule structures and molecule names to become familiar with the IUPAC nomenclature. The following figure describes the IUPAC name of six more substituted alkanes.

The figure shows how the name of an alkane derivative depends on the IUPAC naming rules.

The figure clarifies the naming rules for cyclic alkane derivative structures. Cyclic alkane derivative names depend on the same set of naming rules as those of the straight-chain alkane derivative structures. However, they also include the prefix term “cyclo-” before the ending components of the name like “-pentane” or “-hexane”.

There are an almost unlimited number of different alkanes, but it is interesting to note that there are general trends between the size of an alkane and its physical properties. It has been found that longer alkanes generally have higher boiling and melting points. This trend can be understood if we consider the different chain–chain dispersion interaction forces between short-chain alkanes and longer-chain alkanes.

The dispersion forces depend on both the size and the shape of the interacting alkane molecules. Dispersion forces are stronger when there is more surface area for contact between neighboring molecules. There is generally more surface area for contact between adjacent molecules that are longer and have more carbon atoms, but this simple relationship can be complicated by alkane chain branching. There tends to be more distance between highly branched alkanes because these molecules cannot effectively stack on top of each other.

Example 4: Understanding the Relationship between Alkane Chain Length and Alkane Melting Point

Which of the following alkanes has the highest melting point?

  1. Ethane
  2. Butane
  3. Pentane
  4. Propane
  5. Hexane

Answer

Alkane melting point values are inextricably linked with alkane molecule chain lengths. Longer straight-chain alkanes have higher melting points than shorter straight-chain alkanes. We can determine that hexane has six carbon atoms and that it is the longest molecule from this list of comparable straight-chain alkane molecules. Hexane has the highest melting point because it is the longest of the listed straight-chain alkane molecules. We can use this line of reasoning to determine that option E is the correct answer for this question.

Definition: London Dispersion Force

The London dispersion force is a temporary attractive interaction that exists between any two adjacent molecules that are capable of forming dipoles.

There is a similar relationship between the viscosity and density of a straight-chain alkane and its length. Longer straight-chain alkanes have higher viscosity and density values and shorter straight-chain alkanes have lower viscosity and density values.

Straight-Chain AlkaneChemical FormulaDensity (g/mL) at 20C
PentaneCH5120.626
HexaneCH6140.661
HeptaneCH7160.679
OctaneCH8180.703
NonaneCH9200.718
DecaneCH10220.731

The length of an alkane similarly determines its flammability value. Flammability is defined as the ease with which a combustible substance can be ignited. Longer alkane molecules tend to have lower flammability values and shorter alkane molecules tend to have higher flammability values.

The volatility of a straight-chain alkane can also be determined from its length. Longer straight-chain alkanes have more surface area for contact and they experience stronger intermolecular interactions. The strong dispersion forces make alkanes less liable to spontaneously dissociate from a liquid.

Example 5: Understanding the Relationship between Chain Length and Viscosity

Which of the following alkanes has the greatest viscosity?

  1. Octane
  2. Pentane
  3. Methane
  4. Propane
  5. Ethane

Answer

Alkane viscosity values are inextricably linked with alkane molecule chain lengths. Longer straight-chain alkanes have higher viscosity values than comparable short-chain alkanes. Octane is the longest molecule from this list, and we can therefore surmise that it is the most viscous hydrocarbon. We can use this line of reasoning to determine that option A is the correct answer for this question.

Hydrocarbons are almost always obtained from oil deposits that are discovered underground.

Chemists extract crude oil from large underground reservoirs and then they use fractionating columns to separate the crude oil mixture. The process not only enables chemists to isolate hydrocarbons from other organic compounds, but also enables chemists to separate one type of alkane from another.

The alkanes are then used as a source of energy for planes, trucks, cars, and ships. The energy is obtained by heating the alkanes with a flame and allowing them to react with a plentiful supply of oxygen. This chemical reaction is called complete combustion, and it is always exothermic. The following algebraic formula describes the process of complete combustion for different types of alkanes: CHOCOHO+𝑥+𝑦4𝑥+𝑦2

It is important to appreciate that alkanes can only completely combust when they have enough oxygen gas to react with. Alkanes will only be able to incompletely combust if they cannot interact with enough oxygen molecules. Complete and incomplete combustion can be easily distinguished from each other because incomplete combustion produces carbon monoxide (CO) and complete combustion does not.

Definition: Complete Combustion

The complete combustion of an alkane is an exothermic reaction that produces carbon dioxide and water molecules.

Key Points

  • Alkanes are saturated hydrocarbons that contain covalently bonded carbon and hydrogen atoms.
  • Each carbon atom in any alkane will form four covalent 𝜎 bonds.
  • IUPAC nomenclature specifies how chemists should identify and classify different alkanes.
  • Alkane chain–chain dispersion interaction strength varies with chain length.
  • Longer alkane chains generally have higher phase transition temperatures, viscosity values, and densities.
  • Longer alkane chains are generally less volatile.

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